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April 15, 2013, 07:33 |
BEM Analysis of NREL phase VI turbine
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#1 |
Member
ijaz fazil
Join Date: Apr 2013
Location: Singapore
Posts: 73
Rep Power: 13 |
Hi all
i tired MATLAB code for finding the power coefficient for NREL Phase VI turbine.But my answer is very below the experimental value. i took the hub radius as 1.257 m where the actual airfoil starts I get power coefficent very below the experimental suddenly I got a doubt whether it is because of the hub diameter Actually blade cyclindrical section which is attached is 0.508 m and from 0.883 m to 1.257 m it undergoes transition from cylinder to airfoil. so in BEM I took the hub diameter is 1.257 m where the airfoil starts |
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April 15, 2013, 10:18 |
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#2 |
Member
Kaya Onur Dag
Join Date: Apr 2013
Posts: 94
Rep Power: 13 |
Hello er_ijaz,
The root section shouldn't affect that much actually. What are the expected and calculated power coefficients? |
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April 15, 2013, 10:26 |
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#3 |
Member
ijaz fazil
Join Date: Apr 2013
Location: Singapore
Posts: 73
Rep Power: 13 |
Values of Power Coefficient
windspeed in m/s 7 10 13 15 20 25 experimental(NREL) 0.369 0.209 0.094 0.054 0.0218 0.0149 With out correction 0.304 0.096 0.0035 0.009 0.0053 0.00516 Tiploss correction 0.283 0.0939 0.0118 0.016 0.0060 0.00555 |
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April 15, 2013, 11:32 |
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#4 |
Member
Kaya Onur Dag
Join Date: Apr 2013
Posts: 94
Rep Power: 13 |
First of all, I would include the part from root to the first airfoil section. Than I would compare my Cps with NREL s again.
Still difference? Then I would start having concerns about the tabulated Cl Cd data you use if you got them from another source. (I assume your BEM is correct.. paste your code and I can have a look) |
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April 15, 2013, 11:36 |
can u email me bro
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#5 |
Member
ijaz fazil
Join Date: Apr 2013
Location: Singapore
Posts: 73
Rep Power: 13 |
my email id is er_ijaz@yahoo.com.I,m in mobile.I will forward u my code
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April 15, 2013, 11:41 |
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#6 |
Member
Kaya Onur Dag
Join Date: Apr 2013
Posts: 94
Rep Power: 13 |
would be easier to discuss it here if you paste the main solver here. but you can of course mail me also.
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April 15, 2013, 12:55 |
ur email id
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#7 |
Member
ijaz fazil
Join Date: Apr 2013
Location: Singapore
Posts: 73
Rep Power: 13 |
Brother can i have ur email id .my id is er_ijaz@yahoo.com
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April 15, 2013, 13:04 |
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#8 |
Member
Kaya Onur Dag
Join Date: Apr 2013
Posts: 94
Rep Power: 13 |
gadruno[ at ] g mail.com
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April 15, 2013, 14:22 |
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#9 |
Member
Kaya Onur Dag
Join Date: Apr 2013
Posts: 94
Rep Power: 13 |
I didn't quite understand the way you get the Cl Cd coefficients. Don't you have a tabulated data for it? Or is this a fitted curve provided from NREL?
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April 17, 2013, 05:20 |
regarding cl and cd values
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#10 |
Member
ijaz fazil
Join Date: Apr 2013
Location: Singapore
Posts: 73
Rep Power: 13 |
Hi
i created an empirical formula based on the experimental results by using genetic programming for cl and cd values. And sorry for late reply .I will email u the experimental values other than that did u find any mistakes |
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April 17, 2013, 07:44 |
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#11 |
Member
Kaya Onur Dag
Join Date: Apr 2013
Posts: 94
Rep Power: 13 |
don't send me any data. I don't have time to debug your code yet I can direct you to find your own problem.
plot your measured CL vs aoa - CD vs aoa and plot your CL_empiric - aoa and CD_empiric vs aoa up on them. and lets see how correct your empiric curve. on the other hand, did you check the measured CL and CD whether if its measured at the correct Reynolds? I don't know how big is this turbine but CL and CD datas are very sensitive between RE 100k and 1m. |
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April 17, 2013, 09:04 |
regardin cl and cd
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#12 |
Member
ijaz fazil
Join Date: Apr 2013
Location: Singapore
Posts: 73
Rep Power: 13 |
hi
ya i had plotted n chcked the cl n cd values(empirical) with the experimental.There is no much difference.Anyways thanks for ur help.If u debug pls let me know .anywhere logic is not ok |
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Tags |
aerodynami, nrel phase 6 validation, windturbine |
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