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October 8, 2012, 06:49 |
kinetic energy of rotating fluid flow
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#1 |
New Member
Abbie Chan
Join Date: Oct 2012
Posts: 1
Rep Power: 0 |
Dear all,
For a rotating rigid body which is translating at the same time, the total kinetic energy= translation energy (1/2*mass*velocity^2)+rotational energy (1/2*moment of inertia*vorticity^2). However, would like to ask - for fluid flow which is rotating (such as vortex) and translating simultaneously, does the total kinetic energy=translation energy (1/2*density*velocity^2)+rotational energy (1/2*radius*vorticity^2)?? Thanks! |
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October 8, 2012, 07:20 |
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#2 |
Senior Member
Join Date: Dec 2011
Location: Madrid, Spain
Posts: 134
Rep Power: 16 |
Hi Abbie. No, the kinetic energy of the fluid particles is entirely accounted for in the first term of your equation (1/2*density*velocity^2), because the velocity vector includes the longitudinal and the tangential component. Otherwise you would be accounting for the rotation of the fluid to the kinetic energy twice.
Cheers, Michujo. Last edited by michujo; October 8, 2012 at 09:50. |
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Tags |
kinetic energy; flow |
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