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July 21, 2012, 03:33 |
LES of Turbulent channel flow
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#1 |
New Member
Hamid
Join Date: Mar 2012
Posts: 20
Rep Power: 14 |
Hello CFD guys,
I'm trying to generate turbulent channel flow using wall resolved LES simulation on a collocated block structured, multi-grid accelerated finite volume code. I defined periodic boundaries on the horizontal plane, symmetry on top and no slip wall (no model) for the bottom and started with a log profile with some random noise (10-50% magnitude). The problem is the fluctuations are damped rather quickly. u_tau=1, domain: 0.5pi x 1 x pi with 48*48*48 grids (uniform in horizontal direction and stretched in the vertical with the first grid in yplus=0.25). This could partly make sense as the initial fluctuations are not correlated etc. but there is also a suspicion that since the code is is not pseudo-spectral (unlike many available codes) and is collocated, it's highly dissipative and also not kinetic energy conserving. What is your opinion? Do you have any idea how I should generate the correct turbulence filed? My code has also the problem that the finer the mesh is, the more dissipative it becomes, isn't it strange? |
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July 21, 2012, 04:49 |
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#2 | |
Senior Member
Filippo Maria Denaro
Join Date: Jul 2010
Posts: 6,896
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Quote:
The first issue is that LES is a 3D simulation, you must solve the entire 3D channel, no simmetry at half-height ... you are forcing a false solution |
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July 21, 2012, 08:14 |
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#3 |
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cfdnewbie
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July 21, 2012, 17:46 |
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#4 |
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Hamid
Join Date: Mar 2012
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Rep Power: 14 |
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July 21, 2012, 17:52 |
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#5 | |
New Member
Hamid
Join Date: Mar 2012
Posts: 20
Rep Power: 14 |
Quote:
That's a good point and I agree that LES is in fact 3D, but does it mean you are never allowed to use symmetry BC in LES? Cause I've seen quite a few papers (mainly atmospheric boundary layer simulations) that have set the top BC as a symmetric surface (I guess they've presumed that the top of the domain can be treated like a laminar flow) |
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July 21, 2012, 19:11 |
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#6 |
Super Moderator
Alex
Join Date: Jun 2012
Location: Germany
Posts: 3,427
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There are circumstances when a symmetry boundary condition can be applied in LES. The main prerequisite is that the flow is laminar next to the boundary.
For a turbulent channel flow, this condition is not satisfied. |
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July 21, 2012, 20:38 |
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#7 |
Senior Member
Filippo Maria Denaro
Join Date: Jul 2010
Posts: 6,896
Rep Power: 73 |
in channel flow with LES the condition of simmetry is simply wrong and drives the flow to dissipate artificially the energy ... such a condition can be used in RANS simulation where the variable which is solved has a steady statistical meaning.
Furthermore, I suggest to run the full 3D case with and without SGS model, on the same grid, to assess the real effect of the model... |
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Tags |
channel flow, les, turbulence, wall resolved |
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