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UDF for heat source

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Old   December 16, 2011, 07:54
Default UDF for heat source
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prince
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Hello friends

I got stuck in one problem and will appreciate any help

In my problem there is a heat source of 15KW which will distribute uniformaly in some part of window (over area of 10 cm2 in window zone). I have written simple UDF code to identify the area over which heat has to distributed.

#include "udf.h"
#define CX 0.0
#define CY 0.0
#define CZ 0.0

DEFINE_SOURCE(heat, cell, thread, ds, eqn)
{
real source;
real x[ND_ND];
real r,y, a, b,qr;


C_CENTROID(x, cell, thread);

a = (x[0]-CX)*(x[0]-CX);
b = (x[2]-CZ)*(x[2]-CZ);
r = (sqrt(a + b));
y = x[1];


if(y>1.068798307 && y<=1.070483879)
{
if(r<=0.06)
source=8.39e09;

if(r>0.06)
source=0.0;
}





ds[eqn]=0.0;

return source;
}

My problem is, i am not getting right area over which heat has to distribute.

Thankss
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File Type: jpg geometry solid.jpg (82.9 KB, 7 views)
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