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UDF of shear flows - Just need a little little help |
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July 6, 2011, 12:58 |
UDF of shear flows - Just need a little little help
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#1 |
New Member
Join Date: Dec 2010
Posts: 11
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Hey guys
I've got a little problem about my UDF program to simulate shear flow in Fluent. I finally managed to write the UDF program but there is a little mistake somewhere and I can't manage to fix it. So the geometry of my problem is displayed here -> http://i1129.photobucket.com/albums/...inderinbox.jpg As you can see I want the shear flow to act on the z-axis direction. My UDF program is written as follows: #include "udf.h" DEFINE_PROFILE(yann_x_velocity, thread, position) { real x[ND_ND]; /* this will hold the position vector */ real z; real u0=1.0; face_t f; begin_f_loop(f, thread) { F_CENTROID(x,f,thread); z=x[1]; F_PROFILE(f, thread, position) =1.0+20.0*z; } end_f_loop(f, thread) } Now the problem in Fluent is: When I plot the X velocity profile following a line created on the z-axis, the graph given is http://i1129.photobucket.com/albums/...annossss/1.jpg but this is not the solution I want. On another hand when I plot the X velocity profile following a line created on the y-axis, the graph obtained is http://i1129.photobucket.com/albums/...annossss/2.jpg and this is the graph I'd like to get BUT when I plot the X velocity profile following the line created on the z-axis. I have tried to modify the UDF file but nothing has worked. I'm pretty sure I am very close to the solution but I didn't mange to find and fix the mistake. So if anyone could give me a little help I would really much apprecite it. Thanks for your time guys, I hope you got what my problem is. Yann |
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July 6, 2011, 13:24 |
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#2 | |
Member
Engr Adeniyi
Join Date: Jan 2011
Posts: 32
Rep Power: 16 |
Quote:
I think it should be z=x[3]; to mean z=zaxis because z=x[1]; means z=x axis. At the interface, x=0 in your 3D rectangular geometry. Notice that the velocity is constant meaning the face coordinate is x=0. The plot direction, I think, should be x=1, z=0, y=0 ie in the x-direction in your yannossss/1.jpg not z=1. I suppose all those by using my left hand as the box. Thumb=z axis, first finger=y axis,second finger= x axis, based on your Squarecylinderinbox.jpg Hope am not confusing you ...lol Please confirm am right or wrong. |
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July 6, 2011, 14:21 |
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#3 |
New Member
Join Date: Dec 2010
Posts: 11
Rep Power: 16 |
Thank you very much for the reply unfortunately it does not work.
I also think the mistake comes from the line "z=x[1];" However I made a little mistake on the Squarecylinderinbox.jpg and the right geometry is http://i1129.photobucket.com/albums/...oxmodified.jpg but I don't think it changes the problem. When I plot the X velocity with the plot direction being as you advised me x=1, y=0 and z=0 following the line created on the z-axis it doen't give anything. I mean nothing is plotted. When I do the same but following the line created on the y-axis it gives this http://i1129.photobucket.com/albums/...annossss/3.jpg Hope you're not confused too and still have some ideas in the back of your mind. |
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July 6, 2011, 16:48 |
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#4 | |
Member
Engr Adeniyi
Join Date: Jan 2011
Posts: 32
Rep Power: 16 |
Quote:
I think the system in Fluent is x=x[0],x[1],x[2] and not 1,2,3 so it should be: real x[ND_ND]; /* this will hold the position vector */ real z; real u0=1.0; face_t f; begin_f_loop(f, thread) { F_CENTROID(x,f,thread); z=x[2]; F_PROFILE(f, thread, position) =1.0+20.0*z; } end_f_loop(f, thread) } See the file for my understanding of your model. I like to know if it works. Make sure your axis system is right in Fluent see the x,y,z system and be sure you bind the BC UDF correctly. |
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July 9, 2011, 08:01 |
Problem solved
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#5 |
New Member
Join Date: Dec 2010
Posts: 11
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Hey lad I solved my problem.
So the problem was the cartesian system. In fact the udf is written for my mind with the catesian system I always learnt, meaning: with the right hand, thumb pointing the right designng the x-axis, first finger pointing up designing the y-axis and second finger pointing myself designing the z-direction. It is how Gambit is set and Fluent is also set that way. The problem comes from the reading of the udf file by Fluent. I don't know why but I realised that when Fluent reads the udf file the cartesian system used changes and is defined as: still with your right hand, thumb pointing the right designing the x-axis, first finger pointing in front of you designing the y-axis and second finger pointing up designing the z-axis. Which means that on the udf file, the "z" is read by Fluent as a "y". So in Gambit I just rotated the whole geometry by 90° around the x-axis and modify the equation in the udf file and now when I plot the x-velocity in the y direction (y direction that was the z before of course) it gives me what I'm looking for. Tell me if you understood and thank you very much to have replied quickly to my post to help me. I wish you all the best. Bye bye |
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July 11, 2011, 08:11 |
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#6 | |
Member
Engr Adeniyi
Join Date: Jan 2011
Posts: 32
Rep Power: 16 |
Quote:
Its good to know you have solved your problem. I don't use Gambit. From what you noticed, it is therefore important to see the geometry coordinate system as displayed in Fluent (irrespective of the meshing software). Good luck to you. |
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