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March 16, 2010, 12:45 |
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#21 |
Senior Member
Sebastian Gatzka
Join Date: Mar 2009
Location: Frankfurt, Germany
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How much slower?
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March 16, 2010, 15:09 |
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#22 |
Senior Member
karine
Join Date: Nov 2009
Posts: 158
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Why dont u do a 3D simulation and get a good result?????
even at small sizes, the trajectory of ure bubble is not necesserly vertical (unless it gets near a wall) I am not sure of the ranges of Re with in u get this behavior, but t is due to the instability of the vortex ring. The values of velocity that u are comparing with: are u sure that those experiences have been done in a very clean water???? in normal water, the behavior of bubbles is different. By exemple for stokes regime, the drag will be 24/Re, while it is 16/Re in a very clean water.... |
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March 16, 2010, 15:26 |
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#23 |
Senior Member
Sebastian Gatzka
Join Date: Mar 2009
Location: Frankfurt, Germany
Posts: 729
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Can't blame him. Do you know which computational power he can access?
I'm pretty sure a 3D simulation with acceptable interface resolution will take days ... Lebaigue et. al. (http://test.interface.free.fr/Case01.pdf) have accomplished good results in 2D and Xilaf is simulation even smaller bubbles (and lower Reynolds) ... @Xilaf: What you should check is the approximation of the error the terminal velocity will have inside your domain: Equation (1.4) in the above paper. If this is in the range your bubble rises slower you may want to increase your computational domain.
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Schrödingers wife: "What did you do to the cat? It's half dead!" |
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August 10, 2010, 04:40 |
Divergence detected in AMG solver: x-momentum
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#24 |
Member
ahmad
Join Date: Jul 2010
Posts: 57
Rep Power: 16 |
hi dear all...
i was running fluent solving my 2D case after 35 time step an error message showed up (Divergence detected in AMG solver: x-momentum) i decreased under relaxation factor for momentum from 0.7 to 0.1 but again this message... i will be thankful if u share any similar experience |
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August 10, 2010, 18:54 |
Terminal vel
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#25 | |
Member
Pranab N Jha
Join Date: Nov 2009
Location: Houston, TX
Posts: 86
Rep Power: 17 |
Quote:
@All I am also running simulations of similar nature. I would like to know how to find out the terminal velocity of the bubble in fluent. I got qualitative results of two bubbles rising in a tank (walls have free shear so that they do not affect the bubble). I want to know the Reynold's number. For that I need the terminal velocity. |
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August 11, 2010, 03:23 |
x-momentum
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#26 | |
Member
ahmad
Join Date: Jul 2010
Posts: 57
Rep Power: 16 |
Quote:
i,ve tried all of this,i changed time step from 0.0001 to 1e-7 but no luck and about ur question:in my case rotational velocity is constant but i think u can read velocity from display>xy plot>velocity>... hope it helps |
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August 11, 2010, 14:07 |
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#27 | |
Member
Pranab N Jha
Join Date: Nov 2009
Location: Houston, TX
Posts: 86
Rep Power: 17 |
Quote:
Also, for your problem, I read somewhere (cannot find the reference right now) that if your cell volume is less than 1e-6 cubic meter, then you could try with 3ddp version of fluent instead of 3d. Give it a try and let me know. It worked for me in one case. But have not required it again. |
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August 12, 2010, 02:07 |
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#28 | |
Member
ahmad
Join Date: Jul 2010
Posts: 57
Rep Power: 16 |
Quote:
while ago i tried to open my 2D case with 3D fluent but i faced an error;i'll try that,tnx for ur suggestion
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January 14, 2013, 03:10 |
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#29 | |
New Member
Jieli
Join Date: Oct 2011
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Quote:
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