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June 3, 2009, 07:40 |
Force at wall in pipeflow
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#1 |
New Member
Gunposer
Join Date: Jun 2009
Posts: 8
Rep Power: 17 |
Hi there,
How does Fluent calculate the force at a wall in 2D. Isn't there a prob with the z-cord., to calculate the Area like [latex]$F=0.5\rho v^2 A$[/latex] Greetz Gun |
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June 3, 2009, 09:36 |
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#2 |
New Member
mj sharawi
Join Date: May 2009
Posts: 14
Rep Power: 17 |
Hi
In 2D cases, Fluent calculates the area for a unit width in the z-direction. Whereas in 2D-axi-symmetric, it calculates for one radian rotation. Hope this answers your question. MJ |
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June 8, 2009, 05:01 |
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#3 |
New Member
Gunposer
Join Date: Jun 2009
Posts: 8
Rep Power: 17 |
Thank you for your quick reply,
does it mean, if I've got a wall with units of mm I multiply the "lenght x 1mm" to get the area? |
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June 8, 2009, 06:21 |
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#4 |
New Member
Gunposer
Join Date: Jun 2009
Posts: 8
Rep Power: 17 |
Attached I am sending my problem.
IT is 2D laminar Fluid. The wall in the red frame is called wallleft. Fluent reports me the wallleft force. Now I trie to understand, how Fluent calculate. Density 1400kg/m³ Viscosity 2100Pas v=0.1m/s height = 0.1mm => A=0.1*10^-3 m * 1*10^-3 m = 10^(-7)m² ==> F=7*10^-7 N But is my calculation right. How do I found out the Force at the wall. I dont understand the force report of Fluent, attached to the picture. Hope, somebody can give me support. Greez Gunnar |
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