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April 1, 2009, 09:36 |
Non-Newtonian Flow: Power law (2D BFS)
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#1 |
New Member
Harsh Chaudhary
Join Date: Apr 2009
Posts: 2
Rep Power: 0 |
Hi everyone,
I am a student at IIT Roorkee in India. I am trying to stimulate 2-Dimensional non-Newtonian flow over a backward facing step. I'm using power law model. But I am not getting the correct results. (Interestingly the values of the recirculation length for a particular Re (say 100) match with the value given for twice the value of Re (Here 200) in my reference paper ) The same mesh is generating very good results for Newtonian flow. Re: 50 to 400. n=0.25 Inlet Vel: 2 Inlet Temp: 275k Density and consistency index are manipulated to give Re the desired value. Min Viscosity= e(-10) Max Viscosity= e(+10) Ref Temp= 0 k (This was 273 earlier , no difference occurred) Pressure-Velocity coupling: SIMPLE Discretization> Pressure: Standard Momentum: Power Law Energy: Power Law Please if anyone can spot any problem in these values do inform me. Also if you happen to have some study material\Fluent tutorials related to non-Newtonian flow/Backward Facing step/Power Law or Heat transfer for laminar flow in fluent, please do forward it to me. Any kind of suggestion/guidance will be highly appreciated. Thanks. |
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April 5, 2009, 14:49 |
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#2 | |
New Member
emad khazal
Join Date: Mar 2009
Posts: 23
Rep Power: 17 |
Quote:
I can help you if Please, send me all dimesion of your backward facing step and your reference AND send me your using Re equation With best regards EMAD |
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April 6, 2009, 01:44 |
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#3 |
New Member
Harsh Chaudhary
Join Date: Apr 2009
Posts: 2
Rep Power: 0 |
The dimensions of the (2D) grid are :
upstream 1hX15h downstream 2hX30h here h is the upstream inlet breadth So the step height is 1h. Re= (2h)^n (u)^(2-n) ρ / μ u: inlet velocity (uniform at inlet) n= 0.25 (for validation with ref) rest information is given in my prev post. My reference is a paper by Choi et al. "Numerical study of the impact of non-Newtonian blood behavior on flow over a two-dimensional backward facing step" Biorheology 42 (2005) 493–509 They have taken blood as the reference fluid and used the Carreau model for non-Newtonian flow. I was trying to use power fluid model to regenerate results close to this. I also tried using Carreau model but again the results didn't match. Some of my results: Re=100 Choi (Xr/s) : 2.8 Our result (carreau) (Xr/s): 1.938 Our result (Power law)(Xr/s): 4.82 Re=200 Choi (Xr/s) : 4.8 Our result (carreau) (Xr/s) : 3.877 Our result (Power law)(Xr/s): 8.6 Xr : Reattachment length from step Please do help me out if you find something wrong in this.... Thanks a LOT! |
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April 21, 2009, 04:03 |
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#4 | |
New Member
emad khazal
Join Date: Mar 2009
Posts: 23
Rep Power: 17 |
Quote:
Iam very sorry to late for reply quickly, I run your case and i have same your result. Sorry Many thanks emad |
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