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Unsteady Laminar Flow Around a circular cylinder |
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December 29, 2007, 11:44 |
Unsteady Laminar Flow Around a circular cylinder
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#1 |
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Hi,
I am investigating the behaviour of liquid water around a circular cylinder. Reynolds number is 178, and the velocity is 0.0008942m/s. But I couldn't get the velocity contour as it should be. Here is the image of how it should be. http://img186.imagevenue.com/img.php..._122_425lo.JPG And this is what I got(It is definitely wrong) http://img11.imagevenue.com/img.php?..._122_930lo.JPG Can anybody help me? I chose unsteady solver and laminar for viscous. Time Step Size, Number of Step Size, Max Iter. per Time Step, have they any impact on the result? |
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December 29, 2007, 12:55 |
Re: Unsteady Laminar Flow Around a circular cylind
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#2 |
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Hi, when u are solving unsteady flow time step plays a major role in predicting the physics of the flow. Timestep is calculated based on v=del(x)/del(t) where del t should be ur time step. u can see it in fluent manual how to calculate the time step. if accurate time step is not specified the solution will not be correct.
bye |
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December 29, 2007, 15:03 |
Re: Unsteady Laminar Flow Around a circular cylind
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#3 |
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Thank you very much, Ramesh.K
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December 31, 2007, 01:13 |
Re: Unsteady Laminar Flow Around a circular cylind
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#4 |
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Ramesh is right that time step is very important. In choosing a time step, try to keep the cell CFL (Courant) number to be below 1 near the cylinder. Also, you have to run it long enough to be able to get some vortex shedding and may be need to introduce some perturbation to stimulate shedding.
Sham. |
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January 3, 2008, 06:28 |
Re: Unsteady Laminar Flow Around a circular cylind
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#5 |
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hi, How to calculate the number of time step per iterations in an unsteady problem. thanks in advance
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January 3, 2008, 06:33 |
Re: Unsteady Laminar Flow Around a circular cylind
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#6 |
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In my opinion thats does not really matter as long as your time step size is small enough. In m simulation, it takes about 5 iterations per time step.
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