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August 14, 2007, 06:19 |
Specifying axis of rotation
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#1 |
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Hi everyone
I have a turbine model whose axis of rotation is parallel with the X-axis (it sits 10m above it). When you are choosing values for your fluid zone/wall, how do you specify where the axis is? I am inputting a unit vector value of 1 in the X tab but this isnt relating to the real axis Any help would be great David |
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August 15, 2007, 05:22 |
Re: Specifying axis of rotation
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#2 |
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I had the same problem, but the rotation axis wasn't even parallel to one of those in Fluent. So i went back and created the geometry again. But in your case I think it is not necessary. Try to specify the rotation-axis origin.in order to do this you must pick any point on your axis and check its coordinates.
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August 15, 2007, 06:14 |
Re: Specifying axis of rotation
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#3 |
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Tom
How do I specify the rotation axis origin? Is this done in Fluent? |
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August 15, 2007, 06:50 |
Re: Specifying axis of rotation
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#4 |
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yes in Fluent, define -> boundary conditions -> zonename ->
you will open the window for defining boudary conditions for the zone you are interested in. rotation-axis origin panel is just next to rotation-axis direction panel. |
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November 5, 2016, 15:35 |
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#5 | |
New Member
Guoqing Zhang
Join Date: Nov 2016
Posts: 2
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Quote:
# include "udf.h" # define a0 15791.0742 DEFINE_CG_MOTION(arm_motion,dt,cg_vel,cg_omega,tim e,dtime) { real NV_VEC(axis), NV_VEC(origin); NV_D(origin, =, -37.32952, 5.627642, 0.0); NV_D(axis, =, 0.0, 0.0, 1.0); if(time>=0&&time<0.003) { cg_omega[2]= -a0*time; } else if(time>=0.003&&time<0.007) { cg_omega[2]= -a0*0.003; } else if(time>=0.007&&time<0.010) { cg_omega[2]= -(a0*0.010-a0*time); } else if(time>=0.020&&time<0.023) { cg_omega[2]= a0*(time-0.02); } else if(time>=0.023&&time<0.027) { cg_omega[2]= a0*0.003; } else if(time>=0.027&&time<0.030) { cg_omega[2]= a0*0.010-a0*(time-0.02); } } |
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November 21, 2016, 09:38 |
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#6 | |
Senior Member
Kushal Puri
Join Date: Nov 2013
Posts: 182
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Quote:
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