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May 12, 2006, 10:03 |
Cooling simple 3D geometry problem
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#1 |
Guest
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Dear all, I am very fresh Gambit/Fluent user and need to solve a CFD simple problem on the lend computer. My geomery is very simple: I have (created in inventor and exported as .stp) solid it and cylinder matching this hole that symobolics volume of water. I want to simulate cooling of the solid by water that flows through it. I am playing with this for a long time but noticed no interaction between solid and fluid despite patched temperature difference. I guess that problem is in meshing/setting boundary conditions of the "pipe". Can anyone describe way to mesh it properly in gambit? I tryed to do: - load a solid and subtract a cylinder (to get a solid with hole) and than add a cylinder as a second volume. After that set BC's and mesh - load a solid and cylinder without subtracting and mesh it.
None of these tryes give any "cooling" result in final solution (nor Fluent notices any shadow faces). I would be very grateful for any help, With best regards, Lukasz |
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May 12, 2006, 10:09 |
Re: Cooling simple 3D geometry problem
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#2 |
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Sorry for mistakes, in second line should be "solid and cylinder". The mistake is because I was trying to make solid with hole to avoid subtraction in Gambit.
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May 12, 2006, 10:24 |
Re: Cooling simple 3D geometry problem
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#3 |
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You do not need the cylinder. Just set the inner surface of the solid to be BC as constant temperature (the temperature of the fluid).
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May 12, 2006, 10:39 |
Re: Cooling simple 3D geometry problem
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#4 |
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Dear Sir, I am not quite sure If I understood You well. I assumed that fluid (Water) will be heated by surrounding hot block (which, in turn will be cooled down). So I though that I need fluid zone inside. In the end I am interested in cooling ratio of the block and leaving water temperature as a function of time.
Luk |
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May 12, 2006, 10:47 |
Re: Cooling simple 3D geometry problem
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#5 |
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If you want , send me a scheme of your task and I'll write down what can be done. As I understood you want to see temperature of the fluid and temperature of the solid also. If you do not have fluid flow, then just write: M(fluid).cp(fluid).(t1-tx)=M(solid).cp(solid).(tx-t2)
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