HELP!! Prandtl numbers in RNG k-e turbulence model -- CFD Online Discussion Forums

April 24, 2006, 11:51	HELP!! Prandtl numbers in RNG k-e turbulence model	#1
maoasis Guest Posts: n/a	According to the RNG theory, the inverse effective Prandtl numbers for K and e is about 1.393 in the high-Reynolds-number limit. That means the Prandtl numbers for k and the Prandtl numbers for k e are the same and equal to 0.7179. I want to use RNG k-e turbulence model to run my case --the wind flow through the buildings. I know the contants of Cmu, C1e, C2e, Prandtl numbers for k and Prandtl numbers for e for RNG k-e turbulence model. But how can I define the Prandtl numbers for k 0.7179 and Prandtl numbers for e 0.7179 in Fluent when I use RNG k-e turbulence model?

Posting Rules
You may not post new threads You may not post replies You may not post attachments You may not edit your posts BB code is On Smilies are On [IMG] code is On HTML code is Off Trackbacks are Off Pingbacks are On Refbacks are On Forum Rules

Similar Threads
Thread	Thread Starter	Forum	Replies	Last Post
multiphaseInterFoam for RAS turbulence model	chiven	OpenFOAM Bugs	8	December 6, 2017 03:08
Turbulence Model and limitation to Reynolds number	qascapri	FLUENT	0	January 24, 2011 11:48
Sato's model of bubble induced turbulence	ukbid	CFX	0	January 3, 2011 10:04
effective viscosity in RNG k-e turbulence model	Ellen	Main CFD Forum	1	August 20, 2002 03:20

All times are GMT -4. The time now is 21:42.