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November 3, 2005, 11:12 |
pressure drop / shear rate
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#1 |
Guest
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hi there, i modeled the flow of a polymer through a pipe. i am able to display the temperature of the flow through the pipe and i can see how it cools down. now i have to calculate the shear rate and the pressure drop through the pipe. how can i do that? under: display->contours i can display the temperature and different pressures (static, total, etc). the temperatures are ok, but the pressures a about 1e-6Pa, i cant regocnize a drop of pressure how it is supposed to be...
thanks for your help |
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November 3, 2005, 12:50 |
Re: pressure drop / shear rate
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#2 |
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You can plot the rate of pressure drop at any location. When plotting (or reporting surface intergrals) look under derivatives-> dp/dz, dp/dx, dp/dy.
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November 5, 2005, 10:31 |
Re: pressure drop / shear rate
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#3 |
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Dear Marco, you can use the surface-> point command to make points for example at the inlet and the outlet of the test pipe then go to report->surface integral->vertex average and know the exact pressure at each point , also temperature. By the way, I am modeling water-surfactant solution turbulent flow through pipes , it is a drag reducing flow. Is it the case like you (polymer is drag reducing too). What model do use . If possible, please contact me via aly_wael71@yahoo.com we may help each other. Best regards Wael
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November 7, 2005, 06:50 |
Re: pressure drop / shear rate
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#4 |
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thank you, i wrote a longer email, hope you can help me....
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