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March 28, 2005, 08:22 |
time step size
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#1 |
Guest
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hi, I am a beginner in sliding mesh simulation for stirred tank. I have done MRF and getting satisfactory results. My impeller rotation peed is 270 rpm.(tip speed 1.41 m/s). The problem I am facing is in selecting the time step size. can any one suggest me in getting through this problem. Thanks in advance. Randheer
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March 28, 2005, 19:00 |
Re: time step size
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#2 |
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What is the numerical Scheme you are using. The step size depends on if the scheme is implicit or explicit. If you use an explicit scheme a rough time size would be dt=0.5 dx/C where C is the courant number for the flow. For implicit scheme you can keep much higher time steps. Also since the rotation is 270 rpms try to keep t close to time period of oscillation so that you do not introduce artificial fluctations in the domain.
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March 29, 2005, 04:57 |
Re: time step size
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#3 |
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Dear debs I am using coupled explicit scheme. Please tell me what is dx(is it grid spacing?)and does the period of oscillation is same as the time required for one impeller rotation? thanks Randheer
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March 29, 2005, 13:05 |
Re: time step size
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#4 |
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dx refers to the smallest grid spacing. Period of oscillation is T=2*pi/omega .To ensure stability of your scheme use a lower time step . Google for explicit schemes and you might find literature materials about the neumann analysis for stability of schemes
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