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Can periodic function reduce the time and cost? |
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December 5, 2003, 09:44 |
Can periodic function reduce the time and cost?
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#1 |
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I am modelling a ship propeller now. It is a 3-blade propeller. I am confusing with the ability of periodic function in Fluent. What is the difference on computer power requirement between: I model all the three blades and run in Fluent, and I model one blade and turn on periodic function then run in Fluent. Is the second way less time and cost-consuming?
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December 5, 2003, 11:35 |
Re: Can periodic function reduce the time and cost
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#2 |
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Hi!
It's normal to work with periodib bc in cases like that. Since you have less cells (3 times less in your case) the cpu time will be considaraby smaller. Regards MATEUS |
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December 5, 2003, 13:12 |
Re: Can periodic function reduce the time and cost
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#3 |
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Using periodic condition is a good idea in your case mainly for two reasons:
1) You reduce the complexity of the grid. So it's easier to create your mesh. 2) You reduce computational because, as said by mateus, you have less cell. Hi ap |
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December 8, 2003, 13:24 |
Re: Can periodic function reduce the time and cost
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#4 |
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Thanks. I rotate the propeller using the sliding mesh method. After a few rotations till the efflux established, I retrieve the velocities of the efflux plane. Then, I use the efflux velocities instead of a rotor. This can reduce the use of a sliding mesh method for a long period. Consequently, it reduces the cost and time. Do you think it is workable? If yes, how to do the settings?
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