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October 20, 2000, 15:14 |
Time Steps ?
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#1 |
Guest
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Is it possible to have different flow and reaction time steps in a case ? I'm using Fluent 5.3, single step CH4-Air finite rate chemistry, laminar flow, convective losses to the atmosphere from the geometry and radiation. I need to have variable time steps because chemical and flow time scales in case of laminar flows are many orders of magnitude different.
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October 22, 2000, 19:46 |
Re: Time Steps ?
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#2 |
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Prateep,
if you get anywhere with this, please let me know. I have a similar problem with a chemical reaction in porous media. Regards Greg |
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October 23, 2000, 05:39 |
Call for Maurizio Barbato
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#3 |
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Maurizio, Please try to answer when you have time to read the above message.
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October 24, 2000, 05:41 |
Re: Time Steps ?
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#4 |
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Hi Prateep,
this is a very tough problem. I had to face it with an internal combustion engine where the time step I was using was limited by the chemistry (I was forced to use even 1.0e-7 seconds !). Using a time step "too" long combustion just became an explosion and temperatures went to the hell. Some time strong under-relaxation helped me, but was some rare occasion. In general I think that, unless you set up a sistem to make inner iterations for the chemistry, these phenomena will be the limit for the time step. I know that this means to wait for years in front to your screen, but up to now with Fluent I didn't succeded in having a different solution. May be this is a challenge to rise for the Fluent people. Ciao Maurizio |
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October 24, 2000, 07:25 |
Re: Time Steps ?
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#5 |
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Maurizio, I think that Prateep needs to know how (technically) he can change the time step during calculation at certain time, am I correct Prateep?.
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October 24, 2000, 12:35 |
Re: Time Steps ?
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#6 |
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Hi Maurizio & Hassaneen !
You are right Hassaneen. I'd like to know if I can have two independent time steps in Fluent. Like 10^-7 s for the chemistry and 10^-2 s for the flow. This way I can solve the species and energy eqns separately and couple them to the momentum and continuity after every 10^-2 s. I hope there is a way of doing it, perhaps by writing a UDF. Maurizio, at the moment I'm using a large time step of 10^-4 s and it takes me days to get a solution out (unsteady 1 s data for a FFT). Also, yesterday I tried using 10^-5 s and found that the results come out to be quite different. The selection of the time step has been a headache. On one hand getting results out fast is of paramount importance (otherwise the advisor is not happy!), and on the other hand accuracy is lost. Thanks anyways. Prateep |
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