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ANSYS How do I define a interface is where the electrochemical reaction occur? |
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July 29, 2022, 02:21 |
ANSYS How do I define a interface is where the electrochemical reaction occur?
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sa
Join Date: Jun 2022
Posts: 13
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Hey,
I'm using ANSYS for a electrochemical reaction. The anode side was has a oxidation reaction where hydrogen react with oxygen ion to produce water and electron. The electron will travel to the cathode to reduce oxygen to produce oxygen ion. The oxygen ion travel through the electrolyte to reach with the hydrogen at the anode. My electrolyte is a solid, how do I set it? According the guide , A solid oxide fuel cell works by having electrically conducting porous ceramic electrodes attached on each side of an ionically conducting ceramic material. At the cathode/electrolyte/gas interface, also known as the triple phase boundary, oxygen is reduced to oxygen ions. The oxygen ions are conducted through the oxygen vacancies in the electrolyte to the anode side. At the anode/electrolyte/gas interface, oxygen ions combine to react with hydrogen at the anode electrode to form water and release electrons. The electrons travel through an external circuit to a load and back to the cathode electrode to close the circuit. and The electric field and the electrochemistry interact solely at the electrolyte interface. ANSYS FLUENT treats the electrolyte interface as an impermeable wall. The potential field must have a "jump" condition applied to the two sides of this wall to account for the effect of the electrochemistry. To closely couple the electrochemical behavior to the potential field calculation, you need to include all of the electrochemical effects into this jump condition. It encapsulates the voltage jump due to Nernst, the voltage reduction due to activation, the Ohmic losses due to the resistivity of the electrolyte, and a linearized for voltage reduction due to activation. This interface condition relates the potential on the anode side and the cathode side of the electrolyte and has the following form: Anyone understand how to do this? |
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