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December 12, 2020, 03:05 |
Lower Lift coefficient value
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#1 |
New Member
Join Date: Dec 2020
Posts: 1
Rep Power: 0 |
Hi,
Iam carrying out 2D unsteady simulations of single circular cylinder in Fluent with air as working medium, with Pressure based transient solver. The drag and lift coefficient are not matching with the reference journal values for Reynolds number of 1.3E4, the reported values are drag coefficient as 1.03 and lift coefficient around 0.8. Whereas for 2D steady state simulations of single cylinder, drag coefficient is 1.03 and lift coefficient is 0.2 is obtained from simulations. Below are the setup details in fluent Details : 1) Domain size : 100x30cm 2) Meshing done in ICEM CFD. 3)Reference values: Diameter of cylinder(d) -- 0.01m Area (=Pi*d*d/4) = 7.8525e-05 m2. Length and Depth = 0.01m 5)Boundary conditions: Inlet velocity - 20m/s Outlet - zero gauge pressure Please provide suggestions, to match the drag and lift values for 2D and 3D cases. |
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December 12, 2020, 05:53 |
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#2 | |
New Member
Ajiazi
Join Date: May 2020
Location: Hong Kong
Posts: 23
Rep Power: 6 |
Quote:
you can put the value of diameter in the area and length |
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December 12, 2020, 09:09 |
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#3 |
Senior Member
duri
Join Date: May 2010
Posts: 245
Rep Power: 17 |
The lift coefficient in the cylinder is too high. What is the source of circulation. Since this is an unsteady which quantity are you trying to match, is it average. What about time variation of lift and drag.
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December 12, 2020, 17:31 |
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#4 |
New Member
Ajiazi
Join Date: May 2020
Location: Hong Kong
Posts: 23
Rep Power: 6 |
yes
while calculating time histories for force coefficients, fluent uses reference area, for your case you have a cylinder, you can put cylinder diameter in reference area dialog |
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