CFD Online Logo CFD Online URL
www.cfd-online.com
[Sponsors]
Home > Forums > Software User Forums > ANSYS > FLUENT

Why the transient state initial velocity profile is not identical to the final steady

Register Blogs Community New Posts Updated Threads Search

Reply
 
LinkBack Thread Tools Search this Thread Display Modes
Old   October 14, 2019, 07:27
Default Why the transient state initial velocity profile is not identical to the final steady
  #1
New Member
 
Ahmed
Join Date: Sep 2018
Location: Daejeon
Posts: 8
Rep Power: 8
Ahmed_Sk is on a distinguished road
I am studying flow in a 3D reactor which is rotating due to rotating disk present inside the reactor. Firstly, I simulated it with a steady-state RSM model and a converged solution has been obtained. Later on, I studied it with a Laminar transient state and initialized the flow field with the steady-state solution of RSM.
Now, when the transient state simulation is completed, I extracted velocity profiles at different time steps starting from the 0-time step (0 sec). To my understanding, the velocity profile of the 0-time step should be identical to the velocity profile obtained from RSM steady-state solution. But there is a slight difference in the velocity near the wall of a rotating disk. I am wondering why is that?
I just checked the Solution Methods of both cases. In RSM, I used the SIMPLE scheme with the second order. While, in the Laminar transient state case, I used the PISO scheme with 1st order Momentum. So, are these changes resulting in different velocity values?
I much appreciate if anyone could share his thoughts over it.
Thanks in advance.
Ahmed_Sk is offline   Reply With Quote

Old   October 14, 2019, 13:51
Default
  #2
Senior Member
 
Lucky
Join Date: Apr 2011
Location: Orlando, FL USA
Posts: 5,761
Rep Power: 66
LuckyTran has a spectacular aura aboutLuckyTran has a spectacular aura aboutLuckyTran has a spectacular aura about
RSM the turbulence model? If you run one with a turbulence model and one with a laminar model, of course the results will be different. Turbulent flows are different than laminar flows.
LuckyTran is offline   Reply With Quote

Old   October 15, 2019, 03:22
Default
  #3
New Member
 
Ahmed
Join Date: Sep 2018
Location: Daejeon
Posts: 8
Rep Power: 8
Ahmed_Sk is on a distinguished road
Quote:
Originally Posted by LuckyTran View Post
RSM the turbulence model? If you run one with a turbulence model and one with a laminar model, of course the results will be different. Turbulent flows are different than laminar flows.
Yes, the turbulence model.

You are right. Solver formulations are different from each other and there is no issue in getting different final results as I already got.
But my question is "the initial Laminar transient solution should not be identical to the final steady RANS solution?" Since Laminar transient solver did not start solving it as I extracted result at 0 time-step.
That is why I was hoping for the same results. In fact, they are same but differ in just two points near the wall of the rotating disk.
Please correct me, if my understanding is wrong.
Ahmed_Sk is offline   Reply With Quote

Old   October 15, 2019, 10:04
Default
  #4
Senior Member
 
Lucky
Join Date: Apr 2011
Location: Orlando, FL USA
Posts: 5,761
Rep Power: 66
LuckyTran has a spectacular aura aboutLuckyTran has a spectacular aura aboutLuckyTran has a spectacular aura about
Oh. My mistake, you mentioned a bunch of irrelevant details and fed me a red herring.


They should be identical, they could be identical. But it depends on what steps you used to "initialize" and "extracted." If it's the same mesh, then you shouldn't have to extract or initialize and there would've been a 1-to-1 correspondence.
LuckyTran is offline   Reply With Quote

Old   October 16, 2019, 05:53
Default
  #5
New Member
 
Ahmed
Join Date: Sep 2018
Location: Daejeon
Posts: 8
Rep Power: 8
Ahmed_Sk is on a distinguished road
Quote:
Originally Posted by LuckyTran View Post
Oh. My mistake, you mentioned a bunch of irrelevant details and fed me a red herring.


They should be identical, they could be identical. But it depends on what steps you used to "initialize" and "extracted." If it's the same mesh, then you shouldn't have to extract or initialize and there would've been a 1-to-1 correspondence.
Okay, I accept my mistake of sharing irrelevant details which confused you.

However, the velocity profile is identical everywhere except near the rotating disk. Mesh is the same in both cases. I don't know why is that. Is it due to the friction of the rotating wall which hinders the fluid to flow near the wall?
I initialized the solution in this way: File > Interpolate > write.
Ahmed_Sk is offline   Reply With Quote

Reply

Tags
laminar, rotating flow fluent, rsm, steady state solutionn, transient analisys


Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are Off
Pingbacks are On
Refbacks are On


Similar Threads
Thread Thread Starter Forum Replies Last Post
decompose dependent solution arionfard OpenFOAM 3 December 10, 2018 10:36
Wrong fluctuation of pressure in transient simulation caitao OpenFOAM Running, Solving & CFD 2 March 5, 2015 22:33
pisoFoam with k-epsilon turb blows up - Some questions Heroic OpenFOAM Running, Solving & CFD 26 December 17, 2012 04:34
Orifice Plate with a fully developed flow - Problems with convergence jonmec OpenFOAM Running, Solving & CFD 3 July 28, 2011 06:24
Error while running rhoPisoFoam.. nileshjrane OpenFOAM Running, Solving & CFD 8 August 26, 2010 13:50


All times are GMT -4. The time now is 14:44.