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Using a static void function in Fluent

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Old   October 22, 2018, 04:30
Default Using a static void function in Fluent
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Hanye Azimi
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Hi every body
How could I match a "static void" function to a source term UDF?



This is my function:

static void plung(real time,real *y);
{
real y;
real h,chord,f;
real h1 = h*chord;
real w = 2.0*M_PI*f;
real omega = w*time;
y = h1*sin(omega);
}




Shall I put this function at the source UDF? Or shall I compile it as another UDF?
Thanks in advance
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