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October 2, 2018, 16:03 |
Convergence problem in very simple body
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#1 |
New Member
Valaki Valami
Join Date: Sep 2018
Posts: 14
Rep Power: 8 |
Hello
Iam very new in ANSYS. Iam trying to simulate aluminium container filled up with water and heated from the bottom of the container. The container have a very thin (0.6mm) walls. I cannot reach converging solution. I tried mesh with triangles and with hexa with/without inflation but the result is the same. I dont have any other ideas. Can anyone who is a pro check the mesh or the setup? And help me with good advices, or modidfy the project. Thank you! I put here som pics of the residual, mesh and here is the link for the project: https://files.fm/u/bbv8ng36 |
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October 3, 2018, 22:11 |
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#2 |
Senior Member
Alexander
Join Date: Apr 2013
Posts: 2,363
Rep Power: 34 |
what model settings do you use?
did you try to solve only flow without energy? best regards |
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October 4, 2018, 16:00 |
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#3 |
Senior Member
Join Date: Dec 2016
Posts: 152
Rep Power: 11 |
I don't think this has anything to do with the model settings, but rather how you are actually setting your problem up. I've made up a list of everything I see that is problematic. If you're a newbie, it's totally okay to feel lost in all this stuff. The world of CFD is really complicated, even for those of us who've worked with it for a few years. I highly recommend running through some tutorials that ANSYS offers and reading everything you can on how the program operates. As always, welcome to the forum!
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October 15, 2018, 13:15 |
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#4 |
New Member
Valaki Valami
Join Date: Sep 2018
Posts: 14
Rep Power: 8 |
Thanks a lot for this precise, detailed guidance. After a hard work I can get some solution.
Now, I have container filled with water (not full). The bottom of the container is set to 373K, on the mantle I set natural air convection with 4 W/m2 (see pics.) I compairing laminar flow vs k-epsilon flow. I suprised how big is the temperature difference between the two modes. But more surprisingly is the streamlines. On the laminar flow mode there is a lot of streamlines also I can imagine that the water is flowing like on the picture. But in case k-epsilon flow there is a very few with strange form of streamlines, I cannot imagine that water is going by this way. Why are stramlines so strange on k-epsilon flow and why is so few of them? What is the correct mode for this case? k-epsilon or laminar or something else? I think k-epsilon This was a steady case with 100 number of iterations. Is this enough? |
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October 16, 2018, 00:08 |
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#5 |
Senior Member
Join Date: Dec 2016
Posts: 152
Rep Power: 11 |
Okay, a few questions here. I'm going to try and answer them out of order that you asked, but in an order that I think is most to least important. Cool?
No one here really knows if 100 iterations is enough for your simulation. The main reason? Because we have no way to judge your convergence. One way to judge convergence is by looking at your residuals; if they are below a set value, then you have a "good" solution. I say "good" because you need to see if your set value is low enough to maintain good accuracy. Next, you need to see if the particular quantities of interest (heat on the bottom plate or on the walls of the cylinder) are also converged. This isn't done by monitoring residuals, but by setting up a Surface Monitor (make sure you set it to each iteration, not time step). I'll leave you to read through the manual on how to do that. Basically, you want to make sure that when your solution is "converged" the surface monitor value isn't changing anymore. If it is, then your solution really isn't finished yet. Why are you comparing k-epsilon with laminar flow? As fluid motion is derived not from a pressure difference, but a thermal one, this seems really weird to me. Go back and check your Reynold's number to make sure you have a case that is turbulent before using a turbulence model. You can use both models, but it just more computationally expensive to run more calculations. What made you select k-epsilon? If you're answer is "because it's the most common", go back and read through the different models again. K-epsilon is good with flat plates, but potentially bad with flow separation. This might be all moot, thought, as you may not need a turbulence model at all. I can say with some certainty that your solution for your turbulence model is wrong. The main reason why I can say this is that your temperature variation is non-existent in the turbulence model, so that's bad. Also, your turbulence model has a max volume that is 4 orders of magnitude lower than your laminar model. Check your solution, and see what's up. |
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October 16, 2018, 14:20 |
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#6 |
New Member
Valaki Valami
Join Date: Sep 2018
Posts: 14
Rep Power: 8 |
So, from the laminar model I calculate the Reynolds number: Re = ρ V D/μ = (998 * 0.14834 * 0.445) / 0.001003 = 65682
Where ρ is the density of water = 998 kg/m3 V is the velocity of the fluid, I choose the maximum velocity from laminar solution = 0.14834 m/s D is the diameter (of container?) = 0.445 m μ is Viscosity of the fluid = 0.001003 kg/m*s That is the correct way for calculating Reynolds number? |
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