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pressure surface integral in an axisymmetric problem

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Old   June 7, 2016, 09:55
Default pressure surface integral in an axisymmetric problem
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Clémentine
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Hi everyone,

I'm a beginner at Fluent so I have a very very simple question :
I'd like to know how the pressure surface integral is computed in the case of an axisymmetric problem?
Is it computed all over the body (=rotation about the axisymmetric-axis) or should I multiply the given result by 2*PI or something else?

Thank you
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