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Mesh-motion without a time-step in Fluent

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Old   April 9, 2015, 08:27
Question Mesh-motion without a time-step in Fluent
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Hey everyone,

I want to move the mesh, for a transient calculation. For the mesh motion I have an UDF, that doesn't use the "time" and "dt" from the header, because I calculate the motion in another file. I'm using a pressure based solver, COUPLED and simulating a flow around an object with 2DoF.

The simplified Calculation process is something like this:
A. Reapeat until maxTimestep is reached
1. Repeat until Converged:
i. 10 Iterations
ii. Calculate motion and communicate to fluent
iii. Move Mesh (without taking a "physical timestep")
2. update physical timestep

To move the mesh I use the command mesh-motion and for a transient calculation I have to give it a timestep-size and number of timesteps.

My questions are:
Is the Information for the timestep in the mesh-motion command, for physical timesteps?
If yes:
- Is there another command that triggers the mesh-motion without taking a timestep.
- I've tried to set the time-step-width/number of time steps in the mesh-motion to zero, but then the fluent calculation has an error/doesn't move the mesh.

If No;
- What is the time-step size and the number of time steps used for? I can't find it in the documentation for fluent.

Hope someone knows something about this, it would help alot
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fluent, mesh-motion, physical time, update mesh


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