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How to create hydrostatic pressure in the fluent

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Old   December 14, 2014, 10:59
Default How to create hydrostatic pressure in the fluent
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Ebrahim
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Dear all

How can I create the hydrostatic pressure in the fluent?

for example imagine a pool is filled with water at the beginning(t =0) therefore the water must have hydrostatic pressure in the pool. then another fluid is entered to the bottom of pool under pressure via a pipe.
how can I create the hydrostatic pressure of water

thank you
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Old   December 14, 2014, 17:40
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enable gravity?
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Old   December 15, 2014, 09:41
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yes lucktarn, I select the water as primary phase and enable the gravity. but hte hydrostatic pressure of water doesn't create!
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Old   December 15, 2014, 21:42
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It's because when you enable gravity the pressure is redefined as in equation (7-54) here: https://www.sharcnet.ca/Software/Flu...et_hydrostatic

What you're plotting as static pressure is now p'. If you want to visualize the hydrostatic head, you can quickly define a Custom Field Function that computes p = p' + \rho g y, or just \rho g y.
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Old   December 16, 2014, 16:05
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I usually set operating density to 0 to get hydrostatic pressure (and enable gravity).
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Old   December 17, 2014, 11:49
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can I write an UDF for hydrostatic pressure and apply it to the pressure outlet boundaries to create hydrostatic pressure?
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Old   December 17, 2014, 12:37
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I think the custom field function is easiest to implement.
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Old   December 21, 2014, 10:51
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Dear Luckytran and ghost 82

If I want that at t=0 which there is only water (density =1000) in the whole domain with its hydrostatic pressure and after that another fluid with density 5 is about to enter the domain, I should set the operating density to zero as well ?
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