UDF for Heat Flux

kishan kumar jaiswal · April 11, 2014, 06:16

Dear all,
I am trying to write udf for heat flux having the formula

Q = 0.304/y*y*y

but I am unable to do it. It always shows some error.

Can anyone write udf for heat flux.

y is the length. and Q is the heat flux acting on X-Y plane in Z direction.
Geometry is a cube with dimension 10*5*0.005 all are in meters.
Thanks.

Bionico · April 11, 2014, 11:08

Hello kishan,
is this a boundary condition? In this case I suggest reading Fluent UDF Manual about DEFINE_PROFILE.

Regards

kishan kumar jaiswal · April 12, 2014, 02:35

Dear Bionico,
Thanks for your reply. Yes Its a boundary condition. I am doing the same as u suggested in your reply. but I don't know where I am wrong.

Bionico · April 14, 2014, 03:01

Hello,
can you post your UDF, please?

Regards

kishan kumar jaiswal · April 21, 2014, 19:01

Dear friend,
There are some changes introduced in the formula, right now it is

Q(Y) = (0.304)/(deltaY + deltaY/2)^-3
Where deltaY = 50cm and
Y = 10m

Y is the length on Y-axis and X whixh is equal to 5m is length on X-axis.
Q is heat flux apply on the X-Y plane towards the Z direction.
Geometry is a cube with dimension 10*5*0.005 all are in meters.

If possible please help

Regards,
Kishan

April 11, 2014, 06:16	UDF for Heat Flux	#1
kishan kumar jaiswal New Member Kishan Kumar Jaiswal Join Date: Nov 2013 Posts: 4 Rep Power: 13	Dear all, I am trying to write udf for heat flux having the formula Q = 0.304/yyy but I am unable to do it. It always shows some error. Can anyone write udf for heat flux. y is the length. and Q is the heat flux acting on X-Y plane in Z direction. Geometry is a cube with dimension 1050.005 all are in meters. Thanks. Last edited by kishan kumar jaiswal; April 11, 2014 at 08:18.

April 11, 2014, 11:08		#2
Bionico Senior Member Flavio Join Date: Sep 2011 Location: Brescia, Italy Posts: 181 Rep Power: 16	Hello kishan, is this a boundary condition? In this case I suggest reading Fluent UDF Manual about DEFINE_PROFILE. Regards __________________ Bionico

April 14, 2014, 03:01		#4
Bionico Senior Member Flavio Join Date: Sep 2011 Location: Brescia, Italy Posts: 181 Rep Power: 16	Hello, can you post your UDF, please? Regards __________________ Bionico

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April 12, 2014, 02:35		#3
kishan kumar jaiswal New Member Kishan Kumar Jaiswal Join Date: Nov 2013 Posts: 4 Rep Power: 13	Dear Bionico, Thanks for your reply. Yes Its a boundary condition. I am doing the same as u suggested in your reply. but I don't know where I am wrong.

April 21, 2014, 19:01		#5
kishan kumar jaiswal New Member Kishan Kumar Jaiswal Join Date: Nov 2013 Posts: 4 Rep Power: 13	Dear friend, There are some changes introduced in the formula, right now it is Q(Y) = (0.304)/(deltaY + deltaY/2)^-3 Where deltaY = 50cm and Y = 10m Y is the length on Y-axis and X whixh is equal to 5m is length on X-axis. Q is heat flux apply on the X-Y plane towards the Z direction. Geometry is a cube with dimension 1050.005 all are in meters. If possible please help Regards, Kishan