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Air diffuser velocity magnitude and direction |
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December 27, 2013, 05:36 |
Air diffuser velocity magnitude and direction
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#1 |
New Member
Adam
Join Date: Dec 2013
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Hey guys,
i'm newbie and i hope i post in the correct section. i'm right now try to study the mass flow rate of air at the outlet of a diffuser. We know that to get mass flow rate, we need the average of normal velocity multiply to its cross sectional area. my problem is, how to get air velocity magnitude and direction with respect to surface area (at a certain point)? i know fluent can produce a vector contour, but can i get to the database of the velocity magnitude and direction (for each point)? thx -kenzo- |
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December 27, 2013, 08:57 |
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#2 |
Senior Member
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Location: Germany
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Yes you can access them by UDF but I dunno why you need that!
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December 27, 2013, 12:18 |
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#3 |
Super Moderator
Alex
Join Date: Jun 2012
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Would it not be easier to take the mass flow rate calculated by CFD Post?
This way, you wont even get into trouble when the incompressibility assumption in the formula you described breaks down. |
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December 27, 2013, 23:17 |
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#4 |
New Member
Adam
Join Date: Dec 2013
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Can you please explain more about UDF? My study is actually involve in the accuracy by comparing cfd method with anemometer instrument. So i need cfd data to find velocity magnitude and direction to compare with anemometer reading.
At the end i'll produce correction factor |
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December 27, 2013, 23:21 |
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#5 | |
New Member
Adam
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Quote:
But my study need to know the velocity magnitude and direction at a certain point. Because i need to compare cfd method with anemometer gauge(where anemometer detect velocity at certain place). |
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December 28, 2013, 06:18 |
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#6 |
Senior Member
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then you do not need UDF (own subroutines)
You can plot a line/surface and then post-process the velocity profile along this line for example |
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January 18, 2014, 06:09 |
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#7 | |
New Member
Adam
Join Date: Dec 2013
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Quote:
but i still cant figure out how to get the angle and direction of the velocities. i hope these pictures will help. the last picture is the angle that i need in my study, does the post processing can produce this? or any idea how can i get it? |
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January 21, 2014, 04:55 |
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#8 |
Super Moderator
Alex
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So the angle you are searching for is the one between the positive x-axis and the flow in z-direction?
In this special case, you should be able to create an expression like Code:
atan2(Velocity w,Velocity u) If this is not exactly the angle you are searching for, you can surely find the correct adjustments to the formula. |
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January 22, 2014, 12:54 |
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#9 | |
New Member
Adam
Join Date: Dec 2013
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Quote:
i'll try to use that code. But the exact case is the angle at the surface of my diffuser in each blade (red arrow). I'll provide you this pic to be clear. So basically for a special case, i need to create an expression or code? Thank you again. |
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January 22, 2014, 13:03 |
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#10 |
Super Moderator
Alex
Join Date: Jun 2012
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If you add a coordinate system to your last picture you will be much closer to a solution.
If the directions do not coincide with the main cartesian directions, you can still add a custom coordinate system. |
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February 10, 2014, 05:10 |
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#11 | |
New Member
Adam
Join Date: Dec 2013
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Quote:
i'm a bit confuse to use your given code. can you explain to me more clearly? i mean the basic things to perform that code. Is it udf? i'm really new to this. |
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February 10, 2014, 06:06 |
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#12 |
Super Moderator
Alex
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First you need to create an expression:
expression.png To make the result of the expression available for post-processing, you need to convert it to a variable: variable.jpg Then you can use it just like any other variable to do the post-processing: contour.jpg You should at least do some of the basic tutorials. |
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February 11, 2014, 05:41 |
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#13 | |
New Member
Adam
Join Date: Dec 2013
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Quote:
so we make some custom variable with that expression to project the velocity at certain plane/line right? i'm trying this with simple geometry first and i manage to get the clearer view of the velocities. but how do we extract the information after doing that? i mean the velocity magnitude and direction at that plane/line ? |
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February 11, 2014, 05:44 |
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#14 |
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Alex
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Have you tried to click on "file" -> "export"?
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February 11, 2014, 07:57 |
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#15 |
New Member
Adam
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ohh, so now i get it.
the data from the specific area/line can be obtain in excel format after we "export" it. thank you so much, if i have more question i'll notify here and i'll show my results for others as a guide. |
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March 20, 2014, 09:18 |
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#16 | |
New Member
Adam
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Quote:
thank you so much! |
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March 20, 2014, 10:45 |
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#17 |
Super Moderator
Alex
Join Date: Jun 2012
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I hardly think that there are tutorials for any specific expression.
It just math, so the possible combinations of expressions and variables are infinite. You will have to figure out for yourself if your equations do what you had in mind. |
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March 31, 2014, 08:03 |
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#18 | |
New Member
Adam
Join Date: Dec 2013
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Quote:
to check whether the expression is valid or not, i try another diffuser with 30 degree of blade angle. This is the result. So then, i plot a line in the middle of the diffuser to export for the post processing. I have also draw the angle of velocity that i need to make you understand. noted that with the blade angle of 30 degree, probably the file that in the excel form will get nearly at 30 degree angle of velocity. (Angle normal to the surface of the diffuser outlet). but later i get this "single" (should it be in x,y and z direction?) velocity angle and only between 0-9.45 degree. Oh and this result i tried by using expression "atan2(Velocity w, Velocity u)" i really need to understand how to make correct expressions. Hope you can help me. |
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