Gravity Components for Inclined Channel

ashishme · August 4, 2013, 06:31

Hi, I am a new user to Fluent. I have a 3D inclined channel say 5 degree inclined from horizontal(X-axis) on XY plane. While enabling gravity, what will be the X, Y and Z components of gravity. Flow is from lower to higher elevation. A small explanation would be highly appreciated. Will it be 0,-9.81,0 or 9.81sin5,-9.81cos5,0 or something else?
For a 2D vertical channel(upward flow) X and Y components are 0 and -9.81.(From a Fluent tutorial).

ashishme · August 17, 2013, 04:00

Does anybody have any idea about it??

flotus1 · August 17, 2013, 05:44

The direction of the gravity vector is entirely your choice.
No one here knows in which direction gravity is pointing in your simulation.

ashishme · August 18, 2013, 10:41

Thanks for your reply..Gravity is acting downward.And I want gravity effects to be included..For 5 degree inclination from X-direction(with flow from bottom to higher level)...I guess..there has to be a fixed set of gravity components to see appropriate results(Specially in cases, when flow is in opposite direction,i.e. from higher to lower level,flow will take place just because of gravity.)

ashishme · December 27, 2013, 06:33

I was wondering if anyone could answer that.

Zaktatir · December 27, 2013, 08:54

You have to know that the gravity vector is written as : g(vector): (gx,gy,gz)

A picture of your problem would be better to have an understanding of the orientation of the geometry!

ashishme · December 28, 2013, 02:46

Here is the image. Fluid is flowing from left to right. I need to know the gravitational acceleration components to be entered in fluent general section.
Inclination is 5 degree from horizontal.

ashishme · December 28, 2013, 03:01

In figure it is horizontal(isometric view), but if it has to be inclined at 5 degree from X-axis, how one will incorporate the gravity effects.

Zaktatir · December 28, 2013, 06:03

still the same direction in y-direction (based on your description)

ashishme · December 28, 2013, 06:34

In Y-direction, it will be same as before. Inclination is with respect to X-axis only. Does it make it clearer? Let me know plz.

August 4, 2013, 06:31	Gravity Components for Inclined Channel	#1
ashishme New Member Ashish Jain Join Date: Jul 2013 Posts: 10 Rep Power: 13	Hi, I am a new user to Fluent. I have a 3D inclined channel say 5 degree inclined from horizontal(X-axis) on XY plane. While enabling gravity, what will be the X, Y and Z components of gravity. Flow is from lower to higher elevation. A small explanation would be highly appreciated. Will it be 0,-9.81,0 or 9.81sin5,-9.81cos5,0 or something else? For a 2D vertical channel(upward flow) X and Y components are 0 and -9.81.(From a Fluent tutorial).

Similar Threads
Thread	Thread Starter	Forum	Replies	Last Post
Open Channel Flow	ElanMorin	FLUENT	4	February 25, 2015 17:26
Gravity source term in PisoFoam	DanM	OpenFOAM Running, Solving & CFD	4	May 24, 2013 12:30
Convergence problem when use gravity	aroma	STAR-CCM+	1	April 10, 2013 11:18
Question on Gravity	archdevil	Main CFD Forum	9	May 16, 2012 14:31
tecplot 3D velocity contours inside a channel	vetnav	Tecplot	4	July 14, 2010 21:03

August 17, 2013, 04:00		#2
ashishme New Member Ashish Jain Join Date: Jul 2013 Posts: 10 Rep Power: 13	Does anybody have any idea about it??

August 17, 2013, 05:44		#3
flotus1 Super Moderator Alex Join Date: Jun 2012 Location: Germany Posts: 3,427 Rep Power: 49	The direction of the gravity vector is entirely your choice. No one here knows in which direction gravity is pointing in your simulation.

August 18, 2013, 10:41		#4
ashishme New Member Ashish Jain Join Date: Jul 2013 Posts: 10 Rep Power: 13	Thanks for your reply..Gravity is acting downward.And I want gravity effects to be included..For 5 degree inclination from X-direction(with flow from bottom to higher level)...I guess..there has to be a fixed set of gravity components to see appropriate results(Specially in cases, when flow is in opposite direction,i.e. from higher to lower level,flow will take place just because of gravity.)

December 27, 2013, 06:33		#5
ashishme New Member Ashish Jain Join Date: Jul 2013 Posts: 10 Rep Power: 13	I was wondering if anyone could answer that.

December 27, 2013, 08:54		#6
Zaktatir Senior Member Join Date: Jan 2010 Location: Germany Posts: 268 Rep Power: 17	You have to know that the gravity vector is written as : g(vector): (gx,gy,gz) A picture of your problem would be better to have an understanding of the orientation of the geometry!

December 28, 2013, 03:01		#8
ashishme New Member Ashish Jain Join Date: Jul 2013 Posts: 10 Rep Power: 13	In figure it is horizontal(isometric view), but if it has to be inclined at 5 degree from X-axis, how one will incorporate the gravity effects.

December 28, 2013, 06:03		#9
Zaktatir Senior Member Join Date: Jan 2010 Location: Germany Posts: 268 Rep Power: 17	still the same direction in y-direction (based on your description)

December 28, 2013, 06:34		#10
ashishme New Member Ashish Jain Join Date: Jul 2013 Posts: 10 Rep Power: 13	In Y-direction, it will be same as before. Inclination is with respect to X-axis only. Does it make it clearer? Let me know plz.