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November 28, 2012, 11:33 |
Forces on wall in unsteady case
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#1 |
New Member
Tomek
Join Date: Jul 2012
Posts: 4
Rep Power: 14 |
Hi
I am wondering about how to plot forces that acting on valve wall in unsteady simulation. I now that there is something in ,, monitors'' but only a drag force. But this is not that I want. I would like that y - axis represent force and x- axis represent flow time. Does anybody know how to do it? And my second question is about the metioned drag force. This value is based on referenced values like area and velocity. How to get information what kind of values they should be I dont understand this meaning of reference values. Maybe somebody can explain me this in easy way. |
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November 30, 2012, 22:29 |
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#2 | |
Senior Member
Ovi
Join Date: Oct 2012
Location: Sydney, Australia
Posts: 166
Rep Power: 14 |
Quote:
For the reference values, I would guess that a velocity which represents free-stream values or bulk velocity should be appropriate, since that is what we would manually calculate. I also noticed that the default reference area is 1 m^2 and so far I have always left it at this value. However, this should ultimately be changed to represent the surface area of interest. From my limited understanding it would seem using an area of 1 means that the drag force being calculated is essentially a specific 'per-unit area' value and should be multiplied with the surface area, perhaps in a post-processing application. I am sure someone here will be able to shed some more light on this however, I hope the discussion above helps you. Good luck.
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December 7, 2012, 17:09 |
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#3 |
New Member
Tomek
Join Date: Jul 2012
Posts: 4
Rep Power: 14 |
I am wondering about other method. If I have defined variable in UDF that stores the value of Force. Is there a UDF Function that I can use to plot this variable values?
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December 8, 2012, 08:30 |
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#4 |
New Member
Tomek
Join Date: Jul 2012
Posts: 4
Rep Power: 14 |
Ok I find solution. As you mentioned I specyfy reference values:
velocity 1 m/s density 2 m/s area 1 m^2 And then the Drag Coefficent is exactly as the value of force ( I checked it from force reports). Thank you |
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December 8, 2012, 08:55 |
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#5 | |
Senior Member
Ovi
Join Date: Oct 2012
Location: Sydney, Australia
Posts: 166
Rep Power: 14 |
Quote:
Best of luck with your work.
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-- Mechanical Engineering Sydney, Australia |
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