UDS source term problem

tompa · January 24, 2011, 09:15

i have two uds for scalar n0 and n1

now i want to add a source term "gradient (gradient n1)" in n0's equation

but i only find that gradient n1=C_UDSI_G(c,t,1)

how about "gradient (gradient n1)" ?

gearboy · January 24, 2011, 22:48

Quote:

Originally Posted by tompa

i have two uds for scalar n0 and n1

now i want to add a source term "gradient (gradient n1)" in n0's equation

but i only find that gradient n1=C_UDSI_G(c,t,1)

how about "gradient (gradient n1)" ?

Set another additional UDS2 and let UDS2=C_UDSI_G(c,t,1), Then C_UDSI_G(c,t,2) is what you want.

tompa · January 26, 2011, 03:22

thanks for your anwser. There's another quastion about the error about type of variables.

C_UDSI(c,t,2) can't be equal to C_UDSI_G(c,t,1) seems like

that C_UDSI(c,t,2) is a scalar but C_UDSI_G(c,t,1) is a vector?

January 24, 2011, 09:15	UDS source term problem	#1
tompa New Member tom pan Join Date: Nov 2010 Posts: 14 Rep Power: 16	i have two uds for scalar n0 and n1 now i want to add a source term "gradient (gradient n1)" in n0's equation but i only find that gradient n1=C_UDSI_G(c,t,1) how about "gradient (gradient n1)" ?

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January 26, 2011, 03:22		#3
tompa New Member tom pan Join Date: Nov 2010 Posts: 14 Rep Power: 16	thanks for your anwser. There's another quastion about the error about type of variables. C_UDSI(c,t,2) can't be equal to C_UDSI_G(c,t,1) seems like that C_UDSI(c,t,2) is a scalar but C_UDSI_G(c,t,1) is a vector?