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September 21, 2010, 08:43 |
uds in udf
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#1 |
New Member
arash
Join Date: Aug 2009
Posts: 29
Rep Power: 17 |
I defiened a UDSI in unsteady time. I define such variable in my udf,
(C_T(c,t)-C_UDSI(c,t,0)), I see error |
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September 22, 2010, 00:05 |
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#2 |
Senior Member
MASOUD
Join Date: Mar 2009
Posts: 102
Rep Power: 17 |
Are you sure that the temperature and uds gradient have the same unit? If not you can't define such a term. That could be the reason.
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September 22, 2010, 02:04 |
uds in udf
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#3 |
New Member
arash
Join Date: Aug 2009
Posts: 29
Rep Power: 17 |
thanks for your answer. yes, (C_UDSI(c,t)) and C_T(c,t) both are temperature in Kelvin
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