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Old   June 13, 2016, 04:07
Unhappy Facing Parse Error
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KasrA
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Hi guys,may i have your help on this code ? :/
I faced this error ---> line 47: parse error
and this is my code :
#include "udf.h"

DEFINE_PROPERTY(cell_viscositynano,c,t)
{
double mu;
double h = C_T(c,t);

//mu = exp(3.003- 0.04203*h - 0.5445*1 + 0.0002553*pow(h,2) + 0.0524*pow(1,2) - (1.622/1))/1000;
mu = (-0.155 -19.582/h +0.794*1 +2094.47/pow(h,2) -0.192*pow(1,2) -8.11*1/h -27463.863/pow(h,3) +0.0127*pow(1,3) +1.6044*pow(1,2)/h +2.1754*1/pow(h,2))/1000;


real mu;
}

DEFINE_PROPERTY(thermal,c,t)
{
double mu_lam , k ,Pr ,Re ;
double z = C_T(c,t)- 273;
double a , b , c , d , f ,aa ,bb, cc, dd ,ee;
//double mu_lam;
double t = z + 273;

// u water
a = 98.75*log(z);
b = (-45.23)*log(z)*log(z);
c = (9.71)*log(z)*log(z)*log(z);
d = (-0.946)*log(z)*log(z)*log(z)*log(z);
f = (0.03)*log(z)*log(z)*log(z)*log(z)*log(z);
mu_lam = (-81.1+a+b+c+d+f)/1000;


Re = (997.1*1.3807*pow(10,-23)*t)/(3*3.14* mu_lam * mu_lam * 0.17 * pow(10,-9)) ;
Pr = mu_lam / (997.1 * 1.47*pow(10,-7));


aa = pow(1,0.7640); // volume fraction
bb = pow((0.384/47),0.369);
cc = pow((0.613/25),0.7476) ;
dd = pow(Pr,0.9955);
ee = pow(Re,1.2321);


k = ( 1 + 64.7*aa*bb*cc*dd*ee)*0.613;



real k:
}
Mesh location : C:\Fluent.Inc\ntbin\ntx86\LD0.8-2121
UDF location : C:\Fluent.Inc\ntbin\ntx86\properties-phi9
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Old   June 13, 2016, 04:45
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What is on line 47? And what is that line supposed to do according to you?
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Old   June 13, 2016, 07:00
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real k; and it defines type of variable "k" as real number
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Old   June 13, 2016, 07:04
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Quote:
Originally Posted by kasrakrd View Post
real k; and it defines type of variable "k" as real number
you defined it as a double first and now you are defining it as real (this does not make any sense).

you should " return k; ", not REAL k.
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Old   June 13, 2016, 07:06
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(edit: in response to kasrakrd, not to Bruno Machado): No and mwah.

No: read carefully, your code does not say "real k;", but "real k:".

Mwah: if it would say "real k;", it would still a warning and probably also an error. The warning is because you already defined k as a double. And the error that I expect is because you can not define a variable after you use it.

And your UDF currently returns nothing. I guess that the value you want to use in your simulations is k, so probably you should add "return k" at the end.
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Old   June 13, 2016, 07:07
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Quote:
Originally Posted by Bruno Machado View Post
you define it as a double first and now you are defining it as real (this does not make any sense).

you should " return k; ", not REAL k.
I changed it and i faced this :
line 47: function returning float returns double.
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Old   June 13, 2016, 07:10
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You can get rid of that warning by letting it return a float.
There are multiple ways for that, one of them:
Code:
return (float)k;
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Old   June 13, 2016, 07:43
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Thank you Bruno Machado and pakk
problem solved
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