|
[Sponsors] |
UDF: Have 3 dynamic mesh regions working well in 2D, but not in 3D |
|
LinkBack | Thread Tools | Search this Thread | Display Modes |
October 16, 2015, 21:45 |
UDF: Have 3 dynamic mesh regions working well in 2D, but not in 3D
|
#1 |
New Member
Gabriel Naccache
Join Date: Oct 2015
Location: Montreal
Posts: 1
Rep Power: 0 |
Hello everyone,
So I have done a simulation in 2D where I prescribed the motion of two domains using a UDF. The purpose of this simulation was to analyse the performance of a vertical axis wind turbine with one blade in a non circular path. The entire mesh is composed of an outer deforming stationary mesh, and an inner moving mesh that translates in a vertically oscillating motion. Inside this translating mesh, is another rotating sliding mesh. I have completed the simulation in 2D and everything works fine. So I am testing this design in 3D, but it is not working correctly. The UDF is compiled correctly without any errors. When I launch the simulation, I can see that the mesh does indeed move; however, when I monitor the velocity of the blade, Fluent gives me zero velocity value. So I decided to make a dummy simulation and test each domain motion individually with the UDF and they both worked and fluent gave me the correct velocity on the blade. I have attached the UDF to look at. If anyone could help me with this problem, I would greatly appreciate it. Thanks everyone. Last edited by gabriel09; October 17, 2015 at 17:22. |
|
May 12, 2016, 07:06 |
Dragon fly motion
|
#2 |
Senior Member
Arun raj.S
Join Date: Jul 2011
Posts: 207
Rep Power: 16 |
Hi Gabriel,
I am simualting dragonfly motion. I want to use sliding mesh as I want to create structured mesh around the aerfoil. What changes I have to make in this udf. I have attached my domain. Could you tell me?. I have attached the udf which i have prepared but i am not sure whether it is proper or not x(t),y)(t) = (Ao/2)*(1+cos(2*pi*f*t)*(cos(beta),sin(beta)) alpha(t) = alphao+B sin(2*pi*f*t) Ao=2.5 cm B=pi/4 alphao=pi/4 f=40 Hz beta = 60 degree I have differentiated the above function and applied in the udf vel[0] = - A0/2 * 2*pi*f*cos(beta)*sin(2*pi*f*t) vel[1] = - A0/2 * 2*pi*f*sin(beta)*sin(2*pi*f*t) omega[2]= B *2*pi*f*cos(2*pi*f) |
|
Tags |
3d analysis, fluent, udf cg motion |
|
|
Similar Threads | ||||
Thread | Thread Starter | Forum | Replies | Last Post |
2d Dynamic Mesh with udf | pvc | Fluent UDF and Scheme Programming | 44 | May 19, 2021 19:10 |
dynamic mesh udf | hillat | Fluent UDF and Scheme Programming | 3 | March 1, 2014 17:53 |
Dynamic mesh for rotating wall - UDF ? | Tobard | FLUENT | 1 | April 28, 2011 19:00 |
dynamic mesh udf sample | wlt_1985 | FLUENT | 0 | April 11, 2011 00:36 |
a problem about DEFINE_GEOM in dynamic mesh UDF | speedcat | FLUENT | 1 | May 16, 2005 04:09 |