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March 31, 2015, 11:59 |
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#21 | |
Senior Member
Mr CFD
Join Date: Jun 2012
Location: Britain
Posts: 361
Rep Power: 15 |
Quote:
- Inhomogeneous momentum to allow the phases to separate during evaporation. - Inhomogeneous energy for both phases to allow each phase to have its own temperature fields in order to correctly model evaporation - You can get away with homogeneous turbulence The particle and free surface models aren't sufficient in their formulation for the interfacial area density to model evaporation from the free surface. This means you'll need to go the mixture model route. What does this mean: 1. You need to specify the interfacial length scale (I should have a paper out soon documenting how to get the appropriate length scale for the mixture model in evaporation problems) 2. You need to specify the interfacial drag. The default is 0.44 - however this is for droplets and not a free surface. And lastly, because you'll be using the mixture model you'll need to have two continuous phases (or in your case three!). Water, and water vapour and air above the free surface. Essentially you're solving 3 sets of momentum equations (one set for each material), 2 sets of energy equations (assume the vapour is at Tsat and you don't need to solve the energy equation for vapour), the continuity and volume fraction equations, and your turbulence equations. Basically, what you're after isn't easy. |
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March 31, 2015, 13:36 |
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#22 |
New Member
Join Date: Jan 2011
Posts: 5
Rep Power: 15 |
Ricochet,
This is an interesting view. I understood all your points except the one that you said "Inhomogeneous momentum to allow the phases to separate during evaporation.". Can you please elaborate? Basically, I have water and vapor (lets's just say we have only two phases) which are separated by an interface (I use this as an initial condition). Then, I run the case, and ideally, the interface should move due to the conservation of mass. btw, I did run some simulation with homogeneous approach and captured the interface movement (I am still working on it to make sure it is accurate). Thanks |
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April 1, 2015, 07:10 |
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#23 | |
Senior Member
Mr CFD
Join Date: Jun 2012
Location: Britain
Posts: 361
Rep Power: 15 |
Quote:
You need an inhomogeneous approach to momentum to allow the two phases to "slip" past each other. You control the amount of slip via the drag coefficient. Hint: look at the density ratio of water to vapour at your operating pressure. It's in the order of 1000s. Do you expect a homogeneous momentum approach will successfully model a sudden change in density from 998 kg/m^3 to 0.1 kg/m^3? |
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May 19, 2016, 04:19 |
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#24 | |
New Member
Hilde
Join Date: May 2014
Location: Copenhagen, Denmark
Posts: 18
Rep Power: 12 |
Quote:
Thanks in advance |
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June 1, 2016, 05:53 |
related to fluent
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#25 |
New Member
Moscow
Join Date: Dec 2013
Posts: 4
Rep Power: 0 |
Can you please clarify, what mean inhomogeneous approach related to Fluent case setup. I model evaporation from free water surface in usual room conditions and need any information, how to do it.
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Tags |
evaporation, free surface |
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