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Discrete Data As Boundary Condition in CFX-Pre |
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November 10, 2011, 22:22 |
Discrete Data As Boundary Condition in CFX-Pre
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#1 |
Senior Member
Ashkan Javadzadegan
Join Date: Sep 2010
Posts: 255
Rep Power: 17 |
Hi all,
I have following discrete data of time dependent pressure distribution and I want to impose these discrete data as inlet boundary condition in CFX-Pre. I would be too pleased if anybody help me to do that. Time Pressure 016.54770.0117.88940.0219.67840.0322.8090.0429.51760.0538.46230.0645.17090.0746.95980.0848.74870.0950.53770.152.7739 Thank you very much. AshtonJ |
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November 11, 2011, 01:33 |
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#2 |
Super Moderator
Glenn Horrocks
Join Date: Mar 2009
Location: Sydney, Australia
Posts: 17,872
Rep Power: 144 |
Use a 1D interpolation function.
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November 12, 2011, 00:20 |
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#3 |
Senior Member
Ashkan Javadzadegan
Join Date: Sep 2010
Posts: 255
Rep Power: 17 |
Thanks for your kind reply. I tried to use 1D interpolation function, however, I was asked to enter the coordinate for each pressure value. I'd like to let you know that I have average pressure at each time interval. I mean, at different times, I have pressure values (a time dependent distribution) and don't have the coordinate. Please let me know what the coordinate is for my problem.
Thank you very much AshtonJ |
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November 13, 2011, 18:03 |
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#4 |
Super Moderator
Glenn Horrocks
Join Date: Mar 2009
Location: Sydney, Australia
Posts: 17,872
Rep Power: 144 |
Coordinate? Then you used a 3D interpolation function. You need a 1D interpolation function.
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November 13, 2011, 21:46 |
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#5 |
Senior Member
Ashkan Javadzadegan
Join Date: Sep 2010
Posts: 255
Rep Power: 17 |
Image1 URL: http://imageshack.us/photo/my-images...nfunction.jpg/ Image2 URL: http://imageshack.us/photo/my-images/528/mydata.jpg/ Again thanks for your attention. I attached an image(1D interpolation Funcation.jpg) which shows that for 1D function, I need to specify the coordinate of each value. My data is also attached as an image. Please have a look and let me know how I can use the attached data as BC. Thank you very much AshtonJ |
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November 14, 2011, 06:16 |
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#6 |
Super Moderator
Glenn Horrocks
Join Date: Mar 2009
Location: Sydney, Australia
Posts: 17,872
Rep Power: 144 |
I see. In your case you define pressure as the result unit and time as the argument units. Then your coordinates are (time, pressure).
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