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problem in writing CEL expressions for mesh motion |
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October 19, 2011, 19:11 |
problem in writing CEL expressions for mesh motion
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#1 |
New Member
Join Date: Sep 2011
Posts: 4
Rep Power: 15 |
hello,
I am quite new in CFX . I need to get mesh deformed at boundaries using specified displacement mesh motion and thinking to input x and y components of displacement as CEL expression . my original equation is kind of fourier function and for example the x directional motion equation is x= 20.11+ 8.569 cos 7.854t+3.256 cos 7.854t+.....so on ...can anybody give me instruction that how to write this quation as expression correctly in boundary mesh motion specified displacement . I was trying to write it like xGlobal [mm] = 20.11[mm] + 8.596 [mm] *cos( 7.854 [radian s^-1] * t [s])+........so on.. but it gave error that suucessfully read 13 characters xGlobal [mm] then error detected at 20.11[mm] + 8.596 [mm] *cos( 7.854 [radian s^-1] * t [s])+... can anybody suggest how to write it correctly ... the motion is time dependent................ thanx for reading tc |
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October 20, 2011, 03:35 |
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#2 |
Senior Member
Lance
Join Date: Mar 2009
Posts: 669
Rep Power: 22 |
"suucessfully read 13 characters"
Which in your case would be "=". You dont need the equal sign, instead just type the expression like 20.11[mm] + 8.596 [mm] *cos( 7.854 [radian s^-1] * t [s]) in the input box. |
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October 20, 2011, 13:55 |
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#3 |
New Member
Join Date: Sep 2011
Posts: 4
Rep Power: 15 |
hi
thanx a lot .....now the error message is gone....i think it has worked....but I have another question.......my model is actually a curve tube which i need to bend with respect to time in a periodic motion.....actually the radius of curvature will change sinusoidally ..now my question is the strategy i am planning to apply is like I have written the previous equations in the mesh motion options of x and y component which i guess will move the entire mesh and model with specified displacement......is my way fine to achieve this? if not can u suggest how to make that happen .......thanx again for ur helpful reply.... tc |
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