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May 14, 2011, 07:53 |
Momentum source / porous loss
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#1 |
Member
Join Date: Apr 2010
Posts: 33
Rep Power: 16 |
Hi all,
I am modelling a radiator and want to account for the pressure loss across it. I have data of pressure loss vs velocity. From that data and the depth of the radiator, I worked out my linear and quadratic resistance coefficients. I then set up a test case to see if the CFX model gave me sensible results. I set up a tunnel with the radiator in the middle and a velocity inlet of 10m/s. I used free slip walls. The pressure drop from CFX was 266 Pa and it should be 230. Can anyone please suggest why the two are different? Thanks, ijk |
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May 14, 2011, 09:54 |
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#2 |
Senior Member
Stuart
Join Date: Jul 2009
Location: Portsmouth, England
Posts: 739
Rep Power: 26 |
Have you tried the CFX Catalytic Converter tutorial? That deals with flow through a porous medium and could assist in setting up your model.
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May 15, 2011, 19:51 |
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#3 |
Super Moderator
Glenn Horrocks
Join Date: Mar 2009
Location: Sydney, Australia
Posts: 17,854
Rep Power: 144 |
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May 16, 2011, 09:15 |
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#4 |
Member
Join Date: Apr 2010
Posts: 33
Rep Power: 16 |
Got it solved.
It was a bug in Excel - I plotted a polynomial trendline in excel and the coefficients it gave me were wrong. |
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May 20, 2011, 09:38 |
calculation?
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#5 |
New Member
Greg
Join Date: May 2011
Location: Boise, ID
Posts: 3
Rep Power: 15 |
I'm trying to do the same thing - I have pressure drop vs. flow rate across a filter, and I need to include this loss in my CFX model. Can you share the spreadsheet or at least point me to the equations?
Thanks! Greg |
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May 20, 2011, 11:30 |
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#6 |
Member
Join Date: Apr 2010
Posts: 33
Rep Power: 16 |
I modelled the flow through a radiator so in my case the flow can only go in one direction. Therefore I used the directional loss model.
I simply plotted (pressure drop/depth of radiator) vs. velocity and fitted a second order polynomial to the data points. (this was the problem in excel) The coefficients are the linear and quadratic resistance coefficients. |
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