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May 26, 2009, 20:02 |
Fixed temperature for domain
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#1 |
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Join Date: Mar 2009
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Hello,
I wounder how to apply a fixed temperature to a domain in CFX-Pre? For a boundary condition (2D), there is an option to give a fixed temperature. For a domain (3D), I created a subdomin for the domain (but actually, the submain is the same as the domain). However, there is no option for giving a fixed temperature over the domain. Please let me know how to deal with this problem. Thank you very much. Jaho |
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May 30, 2009, 13:25 |
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#2 |
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You can do an isothermal analysis and set the domain temperature (Domain->Fluid Models->Heal Transfer->Isothermal). But if you have a multidomain situation, then all the domains will be isothermal. You cannot set the temperature for one domain and solve the Energy Equation for another one.
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May 31, 2009, 20:08 |
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#3 |
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Glenn Horrocks
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Hi,
Can you explain why you want one domain to be fixed temperature? Glenn Horrocks |
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June 1, 2009, 11:07 |
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#4 |
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Thank you, Zef. It's helpful.
Have a great day! |
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June 1, 2009, 11:10 |
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#5 |
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For steady state simulation, I wouldl like to set one domain to have a fixed temperature. Actually, one domain is sort of a heat source such as molten metal to be poured continously.
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June 1, 2009, 19:34 |
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#6 |
Super Moderator
Glenn Horrocks
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Hi,
If the region is fixed temperature then why model it at all? Why not just model its boundary on the domain you are modelling as a fixed temperature? Glenn Horrocks |
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June 2, 2009, 11:36 |
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#7 |
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Thank you for your reply, Glenn.
Glenn, I want to know how to model to give a fixed temp. for 3D domain instead of 2D boundary condition... Is there any way? Thanks |
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June 2, 2009, 19:49 |
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#8 |
Super Moderator
Glenn Horrocks
Join Date: Mar 2009
Location: Sydney, Australia
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Hi,
But if you assume it is a fixed temperature then you are not modelling anything so why bother? You can fix values using a heat equation source term to fix the temperature of a region to a value you define. This way you can set one region to have fixed temperature but elsewhere the temperature is calculated as normal. Is this what you want to do? Look in the documentation under source terms. Glenn Horrocks |
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June 4, 2009, 14:21 |
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#9 |
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Hi Glenn,
I am sorry for late reply. Thank you for your help and have a great day. Jaho |
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