Temperature gradient

March 14, 2009, 00:36

Hi, I would like to get some help regarding temperature graident.

What I did is

First, I defined two types of temperature gradient in CEL expression. e.g., TempGradS: Temperature.Gradient

TempGradt: Temperature.Time derivative

Next, I inserted additional variables for these two. In basic settings, variable type is unspecifed and tensor type is scalar.

My questions are

1) This procedure is correct?

2) Does TempGrads (by the above definition and scalar setting in addtional variables) mean a root of (dT/dx)^2+(dT/dy)^2+(dT/dz)^2 ?

3) How to get these two gradients in CSV file format?

Thank you so much and have a great day~!

Jaho

Zef · March 16, 2009, 07:32

Procedure is incorrect, i think. As far as i know, Temperature.Gradient is CFX-Post variable and it is VECTOR variable. To obtain gradient you want simply define CEL expression sqrt(T.Gradient X^2+T.Gradient Y^2+T.Gradient Z^2). It should work.

Zef

March 14, 2009, 00:36	Temperature gradient	#1
jaho Guest Posts: n/a	Hi, I would like to get some help regarding temperature graident. What I did is First, I defined two types of temperature gradient in CEL expression. e.g., TempGradS: Temperature.Gradient TempGradt: Temperature.Time derivative Next, I inserted additional variables for these two. In basic settings, variable type is unspecifed and tensor type is scalar. My questions are 1) This procedure is correct? 2) Does TempGrads (by the above definition and scalar setting in addtional variables) mean a root of (dT/dx)^2+(dT/dy)^2+(dT/dz)^2 ? 3) How to get these two gradients in CSV file format? Thank you so much and have a great day~! Jaho

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March 16, 2009, 07:32		#2
Zef New Member Join Date: Mar 2009 Posts: 13 Rep Power: 17	Procedure is incorrect, i think. As far as i know, Temperature.Gradient is CFX-Post variable and it is VECTOR variable. To obtain gradient you want simply define CEL expression sqrt(T.Gradient X^2+T.Gradient Y^2+T.Gradient Z^2). It should work. Zef