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December 13, 2016, 13:24 |
Torque
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#1 |
New Member
A
Join Date: May 2016
Posts: 21
Rep Power: 0 |
Hi friends , I am simulating a rotor and centrifugal pump diffuser, I have the experimental values, however, the power value of the shaft is not coherent. The equation I use is TORQUE_Z () @ BLADE + TORQUE_Z () @ HUB) * 6 * 183 [rad s ^ -1], where 6 is the number of blades and 183 is the angular velocity. The result is much lower than the experimental value, am I having any errors in the equation? I have already done simulations with 3 models of K-e turbulence, SST and RSM without success. Do I have any term to add with roughness of blades?
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December 13, 2016, 14:34 |
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#2 |
Senior Member
Join Date: Jun 2009
Posts: 174
Rep Power: 17 |
See below my old post related with your question : find how many are missing in your CFD to evaluate torque comparable to test values.
Let me clarify "Pump Efficiency in CFD" for you (and also for many people who have misunderstood it). Below are what you defined, "head (massFlowAve(Total Pressure in Stn Frame )@R1 Outlet-massFlowAve(Total Pressure in Stn Frame )@R1 Inlet)/(ave(Density )@R1 Outlet*g) shaft power abs(sum(Velocity in Stn Frame u * Force X + Velocity in Stn Frame v * Force Y + Velocity in Stn Frame w * Force Z)@Calc Wall Region) * numComponents" The bottom part, what you named "shaft power", is however not the real shaft power because your CFD domain excludes the followings : - Disk friction on the front and back cavities of the impeller - Leakage flow power loss through the front and rear seals - Any power loss due to recirculation flows returning back to the impeller - Bearing windage power losses Therefore, any well-designed pump impeller will show over 90% efficiency from CFD if all of them are excluded in the analysis, and if the bottom is a pure calculation of (Torque x omega) from CFX-Post. No surprises ! The CFD pump efficiency cannot be compared to test efficiency unless all of external parasitic losses are included in CFD (but so much rare cases). In other words, what CFX-Post displays "Pump hydraulic efficiency = (rho * g * Q * dH) / (Torque x omega)" is not a true one, only confusing users. Be careful. |
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December 14, 2016, 11:44 |
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#3 |
Member
turbo4life
Join Date: Nov 2016
Posts: 41
Rep Power: 10 |
A few questions:
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