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sliding mesh or general moving mesh approach? |
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June 11, 2016, 14:53 |
sliding mesh or general moving mesh approach?
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#1 |
Member
ali
Join Date: Feb 2011
Posts: 37
Rep Power: 15 |
Hi,
Is it possible to simulate a rotor-stator problem using the general moving mesh? I mean to define a subdomain and give a rotational speed to it. if yes, then what is the difference of this method with transient rotor-stator (sliding mesh) approach? |
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June 12, 2016, 23:56 |
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#2 |
Super Moderator
Glenn Horrocks
Join Date: Mar 2009
Location: Sydney, Australia
Posts: 17,819
Rep Power: 144 |
Yes, you can do rotating models with moving mesh. Doing it using moving mesh will be much slower, use more memory, be less accurate and be harder to converge. So it is highly recommended to use rotating frames of reference for rotating things.
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January 8, 2019, 08:13 |
How to give sliding or moving mesh in CFX for linear turbine cascade?
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#3 |
New Member
Trot
Join Date: Feb 2017
Posts: 5
Rep Power: 9 |
How to give sliding or moving mesh in CFX for linear turbine cascade?
In linear cascade I cant give rotational axis. here I am attaching the image. I want to move the rod in the Y direction with a particular velocity. Please help https://drive.google.com/open?id=1VY...4c4w0tQUbo7vdG |
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January 8, 2019, 08:36 |
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#4 |
Senior Member
M
Join Date: Dec 2017
Posts: 694
Rep Power: 12 |
In your Domain settings you can set mesh deformation. Within the boundary condition (e.g. at the blade wall) in boundary details a displacement can be defined. However, I am not sure if this is suitable for you.
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January 8, 2019, 19:47 |
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#5 |
Super Moderator
Glenn Horrocks
Join Date: Mar 2009
Location: Sydney, Australia
Posts: 17,819
Rep Power: 144 |
You can define a linear motion with moving mesh as Michael describes. You can also approximate it by using a rotating domain and making the radius of rotation very large. Then the motion it generates will be almost linear. If you use this approach you will find it much faster and easier to converge compared to the moving mesh approach. But the motion will not be perfectly linear, it will curve a little.
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