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Flow over a blunt body - SST turbulence model |
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January 29, 2016, 00:35 |
Flow over a blunt body - SST turbulence model
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#1 |
Senior Member
Bharath kumar
Join Date: Apr 2009
Posts: 169
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Hi to all
I am doing a CFD simulation of flow over a blunt body in CFX 16.1(like flow over a cylider). I am using SST turbulence model and expecting Vortex shedding behind the blunt body.I ran both steady and unsteady runs but i am not getting the Vortex shedding in CFX. However in Fluent with the same setup and with SST turbulence model Vortex Shedding is happening behind blunt body in Steady state itself. Now what controls i can try to get Vortex shedding in CFX? Thanks in advance |
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January 29, 2016, 05:53 |
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#2 |
Super Moderator
Glenn Horrocks
Join Date: Mar 2009
Location: Sydney, Australia
Posts: 17,871
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Go through the general FAQ on accuracy first: http://www.cfd-online.com/Wiki/Ansys..._inaccurate.3F
To capture vortex shedding you will need a good quality mesh, an appropriate time step size (determined by a sensitivity study or some other valid method, not just guessed), good convergence and second order time differencing. |
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January 29, 2016, 08:03 |
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#3 |
Senior Member
Bharath kumar
Join Date: Apr 2009
Posts: 169
Rep Power: 17 |
Hi Glenn
Thanks for your reply.I under stood the things in the link. But how Fluent predicted the Vortex well with the same mesh (7 million nodes with Boundary Layers) as well as same setup of CFX ? |
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January 29, 2016, 08:13 |
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#4 |
Super Moderator
Glenn Horrocks
Join Date: Mar 2009
Location: Sydney, Australia
Posts: 17,871
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When properly set up both solvers are capable of modelling this flow. You obviously have not set CFX up correctly yet.
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January 29, 2016, 09:01 |
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#5 |
Senior Member
Join Date: Jun 2009
Posts: 1,880
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Not sure what you mean by Vortex Shedding, but I am sure there is no way to predict a transient feature using a standard steady state solver.
You may be seeing a solution that is not converging to steady state, but oscillating between two possible solutions, but that is NOT vortex shedding by any means. Be careful how you interpret your results (with any solver). Hope the above helps, |
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January 29, 2016, 11:16 |
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#6 |
Senior Member
Join Date: Jun 2009
Posts: 174
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As you know, the vortex shedding itself is unsteady, and thus the unsteady RANS should be applied. At first, get a steady-state CFX solution, and then switch to the transient. If, even though you already did this, you cannot see the shedding pattern, you had better try RSM (Reynolds stress model) as a turbulence closure that will predict much better than two-equations. Or you can manipulate some factors in the two-equation, like the production limiter (in Advanced control setting) or the curvature scaling factor. There would be some gaps in Cd values between the steady and unsteady solutions, but both should show the large flow separation.
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