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December 10, 2015, 02:32 |
hydraulic diameter
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#1 |
New Member
mehran
Join Date: Dec 2015
Posts: 10
Rep Power: 10 |
hi dears,
wht is the expression of hydraulic diameter for conical tubes? InletDiameter = sqrt(4*area()@Inlet/pi) this is for straight tube so what is expression for conical tube? because hydraulic diameter changes along the tube length. thanx |
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December 10, 2015, 03:23 |
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#2 |
Member
Thomas
Join Date: Dec 2014
Location: Poland
Posts: 49
Rep Power: 11 |
Maybee try use the arithmetic average values of inlet hydraulic diameter and outlet hydraulic diameter?
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December 10, 2015, 03:34 |
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#3 |
New Member
mehran
Join Date: Dec 2015
Posts: 10
Rep Power: 10 |
tanx for your rpy,
i think so , but i want a way that calculate each point nusselt number at that point , this may be give more precise value of nusselt number. |
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December 10, 2015, 03:55 |
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#4 |
Member
Thomas
Join Date: Dec 2014
Location: Poland
Posts: 49
Rep Power: 11 |
I've got idea. Your conial tube is still circular in each 2D section perpedicular to the axis of revolution. For circular tube hydraulic diameter is a normal diameter. Maybee expression for this diameter should look like this:
d=2*sqrt(x^2+y^2)? |
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December 10, 2015, 04:52 |
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#5 |
Super Moderator
Alex
Join Date: Jun 2012
Location: Germany
Posts: 3,427
Rep Power: 49 |
I think you should ask a slightly different question: Is there any point in defining a hydraulic diameter for a conical tube?
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December 10, 2015, 11:31 |
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#6 |
Senior Member
Maxim
Join Date: Aug 2015
Location: Germany
Posts: 413
Rep Power: 13 |
I guess to calculate the Reynolds/Nusselt number? What about the diameter of the tube? I once did some research with stuff build into a canal and I used the distance between to geometries inside the canal...
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December 10, 2015, 12:40 |
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#7 | |
Super Moderator
Alex
Join Date: Jun 2012
Location: Germany
Posts: 3,427
Rep Power: 49 |
Quote:
Otherwise the choice of a "correct" hydraulic diameter is somewhat arbitrary especially for complex (complex as in "not a straight tube") geometries. |
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December 10, 2015, 12:45 |
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#8 |
Senior Member
Join Date: Jun 2009
Posts: 1,873
Rep Power: 33 |
I agree with flotus1 comment.
Perhaps, it will be good to understand why dimensionless numbers are used:
For parameter reduction, we can determine exactly how many independent parameters our problem depends on For parameter correlation, we may (luckily) obtain a single expression that correlates (it is valid) for a general set of problems. Let say for example, transition from laminar to turbulent flow in pipes occurs approximately at Re = 2000. If you use the hydraulic diameter, the shape of the cross section of the tube can be eliminated, but if you use another characteristic length, you may end up with very different criteria. The accuracy of your calculations cannot depend on how you define your characteristic length. By computing Nu number, you are just reducing the data from dimensional to dimensionless, and notice the parameter correlation I described above if any. I would look to see what characteristic length is being used in the literature for this geometry. However, if your geometry is unique, feel free to pick anything that is simple to explain to someone else. Keep in mind that Nu, or Re numbers are useless if the definition of the characteristic length, properties and hydrodynamic conditions are not clearly described. If such information is missing, their values mean nothing. Hope the above helps |
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December 10, 2015, 12:50 |
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#9 |
Senior Member
Maxim
Join Date: Aug 2015
Location: Germany
Posts: 413
Rep Power: 13 |
I agree with you flotus1 and Opaque. I just tried to _guess_ what user meyhan originally would like to achieve with question.
But I suppose he just has to explain himself... Last edited by -Maxim-; December 15, 2015 at 07:02. Reason: typo |
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hydraulic diameter |
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