CFD Online Logo CFD Online URL
www.cfd-online.com
[Sponsors]
Home > Forums > Software User Forums > ANSYS > CFX

HTC and Adiabatic Wall Assumption

Register Blogs Community New Posts Updated Threads Search

Like Tree2Likes

Reply
 
LinkBack Thread Tools Search this Thread Display Modes
Old   April 22, 2015, 06:49
Default HTC and Adiabatic Wall Assumption
  #1
New Member
 
changhee kim
Join Date: Feb 2014
Posts: 18
Rep Power: 12
changhee.kim is on a distinguished road
I'm conducting the pilot calculation to investigate internal flow field in simple duct.

From that, I want to see the htc distribution.

When I used 'defalut' in CFX, htc value can be shown (this values are based on 'wall adjacent temperature.' however, when I applied 'tbulk for htc' in expert parameter, htc value is all zero, exactly.

Why does it happen?

I know that the htc value can be calculated using the turbulent wall function.

What seems to be the problem? I need your help.
changhee.kim is offline   Reply With Quote

Old   April 22, 2015, 08:08
Default
  #2
Super Moderator
 
Glenn Horrocks
Join Date: Mar 2009
Location: Sydney, Australia
Posts: 17,870
Rep Power: 144
ghorrocks is just really niceghorrocks is just really niceghorrocks is just really niceghorrocks is just really nice
Did you enter a valid value for "tbulk for htc"?

Please attach your CCL.
ghorrocks is offline   Reply With Quote

Old   April 22, 2015, 09:19
Default
  #3
New Member
 
changhee kim
Join Date: Feb 2014
Posts: 18
Rep Power: 12
changhee.kim is on a distinguished road
Thank you

I have attached ccl file.
Attached Files
File Type: zip Manifold Model_Pilot Calculation.zip (4.6 KB, 20 views)
changhee.kim is offline   Reply With Quote

Old   April 22, 2015, 09:25
Default
  #4
Super Moderator
 
Glenn Horrocks
Join Date: Mar 2009
Location: Sydney, Australia
Posts: 17,870
Rep Power: 144
ghorrocks is just really niceghorrocks is just really niceghorrocks is just really niceghorrocks is just really nice
Try setting the expert parameter to "300 [K]". Looks like you forgot to give the value units.
ghorrocks is offline   Reply With Quote

Old   April 22, 2015, 09:48
Default
  #5
New Member
 
changhee kim
Join Date: Feb 2014
Posts: 18
Rep Power: 12
changhee.kim is on a distinguished road
Dear ghorrocks,

There is no option to enter the unit for 'tbulk for htc.' I can just enter the number.

I think the unit of this value follows inlet condition.
changhee.kim is offline   Reply With Quote

Old   April 22, 2015, 22:35
Default
  #6
Super Moderator
 
Glenn Horrocks
Join Date: Mar 2009
Location: Sydney, Australia
Posts: 17,870
Rep Power: 144
ghorrocks is just really niceghorrocks is just really niceghorrocks is just really niceghorrocks is just really nice
What thermal boundary condition have you applied to the walls?
ghorrocks is offline   Reply With Quote

Old   April 23, 2015, 04:48
Default
  #7
New Member
 
changhee kim
Join Date: Feb 2014
Posts: 18
Rep Power: 12
changhee.kim is on a distinguished road
I applied adiabatic wall condition at the walls. And total energy equation was solved.
changhee.kim is offline   Reply With Quote

Old   April 23, 2015, 04:58
Default
  #8
Senior Member
 
Thomas MADELEINE
Join Date: Oct 2014
Posts: 126
Rep Power: 12
Thomas MADELEINE is on a distinguished road
your walls are adiabatic (default condition for wall).
so there is no heat flux between the fluid and your walls.

htc (Wall Heat Transfert Coefficient) is calculated by :
Wall Heat Flux / (Twall - Tadjacent or Tbulk)

so here it is 0 divided by something without value (no temperature is given for your walls).

every thing seems normal to me.
Thomas MADELEINE is offline   Reply With Quote

Old   April 23, 2015, 05:14
Default
  #9
New Member
 
changhee kim
Join Date: Feb 2014
Posts: 18
Rep Power: 12
changhee.kim is on a distinguished road
Thanks,

As far as I know, even if I applied adiabatic wall, htc value can be calculated using turbulent wall function. but these values are not real physical quantity.

So I just want to know why htc values are exactly zero after applying Tbulk for htc at expert parameter.
changhee.kim is offline   Reply With Quote

Old   April 23, 2015, 06:11
Default
  #10
Senior Member
 
Thomas MADELEINE
Join Date: Oct 2014
Posts: 126
Rep Power: 12
Thomas MADELEINE is on a distinguished road
I have just checked in the documentation and I confirm that the HTC is calculated from the heat flux :

CFX > Modeling guide > 2. boundary condition modeling > 2.7. Wall > 2.7.5. Heat Transfer > 2.7.5.4. Heat Transfer Coefficient and Wall Heat Transfer Coefficient
Thomas MADELEINE is offline   Reply With Quote

Old   April 23, 2015, 06:55
Default
  #11
New Member
 
changhee kim
Join Date: Feb 2014
Posts: 18
Rep Power: 12
changhee.kim is on a distinguished road
Thank you so much,

I have a little bit confusing

Applying adiabatic wall assumption, htc value is calculate based on wall function (that is, wall function based heat transfer coefficient).

However, after reference temperature was specified, htc value was calculated using newton's cooling law. So I obtained 0 htc value because wall heat flux is zero.

What do you think about it?
changhee.kim is offline   Reply With Quote

Old   April 23, 2015, 07:02
Default
  #12
Super Moderator
 
Glenn Horrocks
Join Date: Mar 2009
Location: Sydney, Australia
Posts: 17,870
Rep Power: 144
ghorrocks is just really niceghorrocks is just really niceghorrocks is just really niceghorrocks is just really nice
Thomas is correct. HTC is calculated from wall heat flux, so if there is zero wall heat flux (as an adiabatic boundary requires) then the HTC=0.

Wall functions do not return a HTC so your explanation is incorrect. Also I have no idea what your sentences "However, after reference .... flux is zero" mean.
sircorp likes this.
ghorrocks is offline   Reply With Quote

Old   April 23, 2015, 07:11
Default
  #13
New Member
 
changhee kim
Join Date: Feb 2014
Posts: 18
Rep Power: 12
changhee.kim is on a distinguished road
In CFX document,

wall heat transfer coefficient is given by the thermal wall function. the theory of thermal wall functions can be found at Heat Flux in the Near-Wall Region in ANSYS CFX-Solver Theory Guide.
changhee.kim is offline   Reply With Quote

Old   April 23, 2015, 08:21
Default
  #14
Super Moderator
 
Glenn Horrocks
Join Date: Mar 2009
Location: Sydney, Australia
Posts: 17,870
Rep Power: 144
ghorrocks is just really niceghorrocks is just really niceghorrocks is just really niceghorrocks is just really nice
Yes, that is correct. Thomas's posts #8 and #10 describe how the HTC is calculated from the thermal wall function.
ghorrocks is offline   Reply With Quote

Old   April 23, 2015, 08:25
Default
  #15
New Member
 
changhee kim
Join Date: Feb 2014
Posts: 18
Rep Power: 12
changhee.kim is on a distinguished road
Thank you for your help. That is very helpful.
changhee.kim is offline   Reply With Quote

Old   April 23, 2015, 10:55
Default
  #16
Senior Member
 
Join Date: Jun 2009
Posts: 1,880
Rep Power: 33
Opaque will become famous soon enough
As far as I can read in the documentation, the behavior you observed is described here

Quote:
CFX-Solver Modeling Guide

Chapter 17: Expert Control Parameters | 17.3. CFX-Solver Expert Control Parameters |

tbulk for htc

When the Heat Transfer Coefficient (HTC) is computed for a temperature specified wall, by default a near-wall fluid temperature is used for a temperature scale. However, for consistency with traditional 1D analyses, you may want to enter a reference bulk temperature to compute the HTC. This parameter is that reference value.

Thus the HTC computed when this parameter is provided is equal to the local heat flux calculated by the solver divided by the difference of the specified wall temperature and this specified bulk temperature.
I read that as "once you use this parameter, the HTC is evaluated as described here and not elsewhere"

Hope the above helps,
Opaque is offline   Reply With Quote

Old   June 11, 2015, 21:43
Default
  #17
Member
 
Shane
Join Date: Oct 2009
Posts: 52
Rep Power: 17
sircorp is on a distinguished road
Quote:
Originally Posted by ghorrocks View Post
Thomas is correct. HTC is calculated from wall heat flux, so if there is zero wall heat flux (as an adiabatic boundary requires) then the HTC=0.

Wall functions do not return a HTC so your explanation is incorrect. Also I have no idea what your sentences "However, after reference .... flux is zero" mean.
In relation to HTC I need bit help.

Some expert help please. "Pipe(inside) Cooling Test"

I have insulated copper pipe(Filled with Secondary Fluid). During cooling test, the cooling fluid (Primary Fluid) is injected inside the pipe vertically to carry out cooling test for both Secondary Fluid & Pipe Walls.

In Fluent, I set the temperature settings of the wall (pipe material, properties wall thickness and insulation material, properties & thickness and pipe wall temperature).

Problem is system is assuming my Wall Temperature stays constant which is not the case. Pipe should cool as the fluid starts flowing inside the pipe, but does not (heat source was switched off prior to "Cooling Test", so there is no heat source)

The fluid (inside the pipe, Pipe was filled with a Fluid & Heated Prior to Cooling Test) starts cooling down but Copper Pipe temperature stays same.

I only meshed the Fluid Zone not the Pipe's ? Pipe is added in the wall boundary conditions.

How to couple the pipe cooling with inside fluid cooling ?

Help is highly appreciated.

Thanks

Shane
sircorp is offline   Reply With Quote

Old   June 11, 2015, 22:22
Default
  #18
Super Moderator
 
Glenn Horrocks
Join Date: Mar 2009
Location: Sydney, Australia
Posts: 17,870
Rep Power: 144
ghorrocks is just really niceghorrocks is just really niceghorrocks is just really niceghorrocks is just really nice
Sounds like you need to think about what is really happening. If you apply a defined temperature on the walls then of course you won't get any cooling as you have defined it to be fixed. You need to think about what are appropriate initial and boundary conditions so the correct physics can occur.

I suggest you should consider an initial condition of your fixed temperature, with the wall being a convective boundary condition.
ghorrocks is offline   Reply With Quote

Old   June 12, 2015, 08:36
Default
  #19
Member
 
Shane
Join Date: Oct 2009
Posts: 52
Rep Power: 17
sircorp is on a distinguished road
Quote:
Originally Posted by ghorrocks View Post
Sounds like you need to think about what is really happening. If you apply a defined temperature on the walls then of course you won't get any cooling as you have defined it to be fixed. You need to think about what are appropriate initial and boundary conditions so the correct physics can occur.

I suggest you should consider an initial condition of your fixed temperature, with the wall being a convective boundary condition.
Thanks Ghorrocks for the prompt response.

(During experiments, I did record temperature and pressure both along radial and axial directions. Since fluid is highly viscous so I needed to record radial temperature too)

Back to CFD, since walls are part of the system (no heat source) I have created a new geometry where pipe becomes part of the system.

Only bad part is I got several hundred walls and interfaces now. In case of error tracing them is a slight issue.

I need to get correct numbers for pipe cooling else it will be difficult to valid the model in a two phase viscous fluid.

With Regards

Shane
sircorp is offline   Reply With Quote

Old   June 12, 2015, 10:15
Default
  #20
Senior Member
 
Thomas MADELEINE
Join Date: Oct 2014
Posts: 126
Rep Power: 12
Thomas MADELEINE is on a distinguished road
Since there is no big change in the flow (except for temperature) the thing you can do is extract the HTC (W/mē/K) from a steady state simulation with a rough temperature at wall. This value should be more or less constant no matter of the wall temperature.
and export it to a mechanical software for a transient run.

It is not the most accurate simulation but you don't have to get all the interfaces right.

2nd choice :
on CFX you can create a solid domain and create interface for only heat flux.
I think the same is available on Fluent but I don't know this software as well as CFX.
sircorp likes this.
Thomas MADELEINE is offline   Reply With Quote

Reply

Tags
cfx, heat transfer


Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are Off
Pingbacks are On
Refbacks are On


Similar Threads
Thread Thread Starter Forum Replies Last Post
how to find HTC in fluent vallarasu FLUENT 0 December 31, 2013 01:37
calculation of htc christopher0 Main CFD Forum 3 April 7, 2010 04:09
Concentric tube heat exchanger (Air-Water) Young CFX 5 October 7, 2008 00:17
HTC and adiabatic wall Alba CFX 4 November 26, 2007 13:52
HTC w/ adiabatic wall Kali CFX 11 August 7, 2007 11:20


All times are GMT -4. The time now is 16:22.