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A Cylindrical Coordinate Frame problem in CFX |
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March 26, 2015, 11:14 |
A Cylindrical Coordinate Frame problem in CFX
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#1 |
Member
Join Date: Aug 2012
Location: Italy
Posts: 68
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Hello,
I would like to create a velocity profile at the inlet side of a duct, obviously due to the presence of the boundary layer. Since CFX works in terms of Cartesian coordinate system, how can I do it? I've read all the previous posts I could find regarding this topic, but, unfortunately, nothing has really helped me Thanks a lot in advance |
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March 26, 2015, 11:51 |
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#2 |
Senior Member
Thomas MADELEINE
Join Date: Oct 2014
Posts: 126
Rep Power: 12 |
you can have cylindrical component in CFX or create your own component system with CEL expressions.
I don't understand why you want to model the boundary layer in the inlet face... Do you know the size of the boundary layer here ? it can vary quite a lot from what there is before... you can always extend your domain just a little (10 cells in duct direction) and add a free slip wall to avoid the boundary layer problem, but then you will have a very small boundary layer. Or you can use the massFlow option as inlet and let CFX do the rest, but i am not sure it will be more accurate... |
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March 26, 2015, 12:01 |
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#3 | |
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Join Date: Aug 2012
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Quote:
The inlet duct is extremely long. I think that I can avoid modeling the ENTIRE duct if I model a velocity profile according to the equation v/vinf = (y/d)^(1/n) being v = local velocity; vinf = velocity outside the boundary layer; y = distance from wall; d = local boundary thinckness; n =7-9 It would be extremely helpful if you could add some more details on "create your own component system with CEL expression". Thanks again for your help |
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March 26, 2015, 12:03 |
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#4 | |
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Quote:
d = 0.270 * l * Rel ^(-1/6) (if n = 9), being l the duct lenght |
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March 26, 2015, 12:26 |
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#5 |
Senior Member
Thomas MADELEINE
Join Date: Oct 2014
Posts: 126
Rep Power: 12 |
If you know your geometry well enough to have the equation of your inlet circle then you can create your own components:
supposing C the center of your circle Xc the X coordinate etc... create a new expression R = sqrt( (X-Xc)² + (Y-Yc)² for a circle in the XY plane then create the function V(R) and use it as velocity inlet... I don't know by heart the name of CEL function so don't copy paste... |
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March 26, 2015, 12:27 |
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#6 |
Member
Join Date: Aug 2012
Location: Italy
Posts: 68
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.... THANKS A LOT! It was the help I neeeded!
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