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question on simulating rotating channel with a pressure gradient |
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January 14, 2014, 09:35 |
question on simulating rotating channel with a pressure gradient
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#1 |
Senior Member
Huang Xianbei
Join Date: Sep 2013
Location: Yangzhou,China
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hi everyone
I'm doing a simulation on the rotating channel in which the water is driven by pressure gradient. I think it's reasonably to use momentum source to implement the pressure gradient for the dimension of pressure gradient is just the same as the momentum source, kg m^-2 s^-2. The channel is rectangular and the rotating axis is set at the center of the left face where x=0, the x direction is the streamwise ,and the z axis is the rotating axis, y is spanwise. z and x direction are set with 2 pairs of periodic interfaces to make the flow fully developed. However, the results shows no asymmetry aross the y direction and the speed in the x direction is far away from expected, is this method wrong or in other words, no suitable in this problem? |
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January 14, 2014, 17:57 |
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#2 |
Super Moderator
Glenn Horrocks
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Please post an image of what you are modelling and an image of what you are seeing in the results.
Accuracy is an FAQ: http://www.cfd-online.com/Wiki/Ansys..._inaccurate.3F |
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January 14, 2014, 22:45 |
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#3 | |
Senior Member
Huang Xianbei
Join Date: Sep 2013
Location: Yangzhou,China
Posts: 302
Rep Power: 14 |
Quote:
the calculation domain is as the image shows[IMG]C:\Users\dodo\Desktop\QQ截图20140115104337.png[/IMG] here is the result, it's interesting to find that the slop of the calculation curve is the same as the slop in theory, but the y axis U is about 20 time larger than the theory |
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January 14, 2014, 22:50 |
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#4 |
Super Moderator
Glenn Horrocks
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The attached images did not work, please try again.
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January 14, 2014, 22:53 |
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#5 |
Senior Member
Huang Xianbei
Join Date: Sep 2013
Location: Yangzhou,China
Posts: 302
Rep Power: 14 |
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January 14, 2014, 23:04 |
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#6 |
Super Moderator
Glenn Horrocks
Join Date: Mar 2009
Location: Sydney, Australia
Posts: 17,871
Rep Power: 144 |
No, you cannot see files on your local computer over the web. Not unless your PC is a web server that is
You will have to upload it to the forum. |
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January 14, 2014, 23:39 |
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#7 | |
Senior Member
Huang Xianbei
Join Date: Sep 2013
Location: Yangzhou,China
Posts: 302
Rep Power: 14 |
Quote:
the non-dimensional velocity U is done by u/ut, u is the dimensional velocity and ut is the friction velocity which is a constant, in the tunnel flow theory, the slope of the U curve is about -2w, y is the non-dimensional variable which implies the y direction,y=-1 and +1 refers to suction side and pressure side of the channel. The second picture is the calculation domain of the tunnel, the flow is in the x direction and the whole tunnel rotates with z axis which is set at the center of the left side of x direction surface. Both the x and z direction were set with a pair of translational periodic interfaces. |
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January 14, 2014, 23:41 |
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#8 |
Super Moderator
Glenn Horrocks
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I have no idea what the diagram means, what the graph is of and what your flow is. Please put some description on your images so we can understand it.
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January 14, 2014, 23:50 |
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#9 |
Senior Member
Huang Xianbei
Join Date: Sep 2013
Location: Yangzhou,China
Posts: 302
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here is the results of DNS, and the condition I chose is Ro=0.5, it's obvious that the U is far away from the DNS results |
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January 14, 2014, 23:53 |
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#10 |
Super Moderator
Glenn Horrocks
Join Date: Mar 2009
Location: Sydney, Australia
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You still have not explain what the graph is and what the diagram means. I just see a box.
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January 15, 2014, 00:00 |
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#11 | |
Senior Member
Huang Xianbei
Join Date: Sep 2013
Location: Yangzhou,China
Posts: 302
Rep Power: 14 |
Quote:
Thank you for your advise. I tried my best to explain the problem now, if there is any misunderstanding, I'll go on to explain more details |
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