Variable values in CFX expressions

saisanthoshm88 · July 1, 2013, 17:03

In the following expression -

((T/273[K]))^(1.81)*(101330[Pa]/Pref )*2.305e-5[m^2 s^-1]

What kind of averaging is applied in CFX (CFD Post) to the temperature(T), i.e.., is it mass averaged or volume averaged or any other averaging is applied.

Could some one please explain this.

ghorrocks · July 1, 2013, 19:58

Are you calculating this function on the nodal values or over some form of average over a mesh object?

saisanthoshm88 · July 2, 2013, 02:08

Hi Glenn,

No I did not average it over any object, I'm evaluating it just the way it is I mean it is evaluated as itself and not by passing it as an argument to some averaging function

ghorrocks · July 2, 2013, 08:54

Then it is calculated directly on the nodal values with no averaging, and returns a value at each node. Or are you asking what is the basis of the nodal values of temperature?

saisanthoshm88 · July 2, 2013, 09:04

Thanks for the clarification Glenn, No im not asking about the basis, like i know that the nodal values are just a part of the solution and your reply clarified my question.

July 1, 2013, 17:03	Variable values in CFX expressions	#1
saisanthoshm88 Senior Member --------- Join Date: Oct 2010 Posts: 303 Rep Power: 18	In the following expression - ((T/273[K]))^(1.81)(101330[Pa]/Pref )2.305e-5[m^2 s^-1] What kind of averaging is applied in CFX (CFD Post) to the temperature(T), i.e.., is it mass averaged or volume averaged or any other averaging is applied. Could some one please explain this. __________________ Best regards, Santhosh.

July 2, 2013, 02:08		#3
saisanthoshm88 Senior Member --------- Join Date: Oct 2010 Posts: 303 Rep Power: 18	Hi Glenn, No I did not average it over any object, I'm evaluating it just the way it is I mean it is evaluated as itself and not by passing it as an argument to some averaging function __________________ Best regards, Santhosh.

July 2, 2013, 09:04		#5
saisanthoshm88 Senior Member --------- Join Date: Oct 2010 Posts: 303 Rep Power: 18	Thanks for the clarification Glenn, No im not asking about the basis, like i know that the nodal values are just a part of the solution and your reply clarified my question. __________________ Best regards, Santhosh.

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July 1, 2013, 19:58		#2
ghorrocks Super Moderator Glenn Horrocks Join Date: Mar 2009 Location: Sydney, Australia Posts: 17,854 Rep Power: 144	Are you calculating this function on the nodal values or over some form of average over a mesh object?

July 2, 2013, 08:54		#4
ghorrocks Super Moderator Glenn Horrocks Join Date: Mar 2009 Location: Sydney, Australia Posts: 17,854 Rep Power: 144	Then it is calculated directly on the nodal values with no averaging, and returns a value at each node. Or are you asking what is the basis of the nodal values of temperature?