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Nusselt number or heat flux along a pipe wall |
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December 3, 2018, 12:04 |
Nusselt number or heat flux along a pipe wall
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#1 |
New Member
Argenis
Join Date: Dec 2018
Posts: 7
Rep Power: 7 |
Hello everyone, I'm simulating a double pipe counterflow heat exchanger (2D axisymetrical), my thermal boundaries conditions are inlet temperatures, and I want to get heat flux along the pipe to then calculate Nusselt number along the pipe. I'm not trying to find the total heat flux, I want to get heat flux at every x location (along the pipe), and then calculate Nusselt number at every x location (along the pipe). Is there anyway I can get this? Again, I'm not trying to get what you find in heat transfer literature, where Nu sub x is Nusselt number untill that x location, I want to get Nusselt number AT that x location in this way: q=h*ΔT ; Nu= hD/k; Nu= q*D/(ΔT*k) So, if I can get heat flux (q) at any x location I would be able to find Nusselt number at any x location along the pipe. That's what I have in mind, and I would like to know if this is possible. (No matter if I have to use a UDF). |
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December 6, 2018, 13:18 |
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#2 |
Senior Member
Erik
Join Date: Feb 2011
Location: Earth (Land portion)
Posts: 1,188
Rep Power: 23 |
Check out the FAQs:
https://www.cfd-online.com/Wiki/Ansy...ficient_in_CFX |
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December 6, 2018, 13:47 |
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#3 |
New Member
Argenis
Join Date: Dec 2018
Posts: 7
Rep Power: 7 |
Can I do that in fluent? I don't know much cfx
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December 11, 2018, 22:41 |
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#4 | |
Senior Member
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Quote:
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December 14, 2018, 16:37 |
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#5 |
Senior Member
Lucky
Join Date: Apr 2011
Location: Orlando, FL USA
Posts: 5,753
Rep Power: 66 |
The surface heat flux is readily available is it not?
But since Nusselt number isn't a field variable, you do have do something special to convert the heat flux into Nusselt number. I.e. export it out of Fluent and then calculate it, or you must use a udf to calculate it within Fluent. |
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December 14, 2018, 16:51 |
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#6 | |
New Member
Argenis
Join Date: Dec 2018
Posts: 7
Rep Power: 7 |
Quote:
Yes, I'm going to get heat flux this way: q= k*dT/dY, and then Nusselt Number (out of fluent). I have only one doubt, dT/dY is calculated as dT/dR when the axisymmetric condition is enabled? |
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December 14, 2018, 19:25 |
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#7 |
Senior Member
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Tags |
heat exchanger two fluids, nusselt local |
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