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Old   May 3, 2010, 06:09
Default saved data recomputation ....
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hello

Is it possible to recompute a OpenFoam calculation to continue it?
If so, somebody knows how we can do that?

thank you
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Old   May 6, 2010, 02:14
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Quote:
Originally Posted by laurencep View Post
hello

Is it possible to recompute a OpenFoam calculation to continue it?
If so, somebody knows how we can do that?

thank you
If you mean continuing from an existing calculation, then the entry
Code:
startFrom       latestTime;
within the system/controlDict will do that. This also happens to be the default if the "startFrom" entry is completely missing. With this you can simply remove any unwanted time directories to define the latest time for a subsequent restart.
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Old   June 3, 2010, 15:55
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Ben K
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Is there any way to call this while my solver is running?

For example, I'm trying to implement variable deltaT (time step) and if I pick a deltaT that is too high and the solution starts to diverge, I want to restart my simulation based on the latestTime.

Any ideas on how to do this? I've tried using:

runTime.setTime(latestTime, latestTime)
where latestTime = the last stored solution.

When I do this, it does reset the time but it doesn't read the stored solution at latestTime, instead it restarts based on the solution that was previously diverging.
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Old   June 7, 2010, 05:43
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Ben, you could try using storeOldTime() and oldTime(). Or maybe you can find some other ideas in the following thread:
http://www.cfd-online.com/Forums/ope...-openfoam.html
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Old   June 7, 2010, 12:14
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Hmm, I thought that I could just reset the time, as I did above and then read in the stored data using:

Code:
volScalarField scalarName
(
    IOobject
    (
        "scalar",
        runTime.timeName(),
        mesh,
        IOobject::MUST_READ,
        IOobject::AUTO_WRITE
    ),
    mesh
);
when I do an Info << runTime.timeName() << endl; I get the proper time (ie, the old time that I'm trying to revert back to) but for some reason even this doesn't read in the old stored solution.
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Old   June 7, 2010, 16:51
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Ok, so I know what my problem is but I don't know how to fix it.

I detect whether my solution is diverging using a flag and if it's diverging i have:

Code:
 if (diverging == 1) {

    //reset time to last good time
    runTime.setTime(lastStoredTime, lastStoredTime);

    //read the solution from the last good time
    volScalarField scalar(IOobject("scalar",runTime.timeName(),mesh,IOobject::MUST_READ,IOobject::AUTO_WRITE),mesh);
    
}
The problem that I have is that this will read in the old solution correctly but it creates a new volScalarField that only exists within the if {} statement and not outside the if {} statement. It also creates a new volScalarField when all I want to do is replace the old one.

So one idea that I have is to read in the old solution into a temporary volScalarField and then copy the temporary field to the proper volScalarField. How do I copy the temporary volScalarField into my actual volScalarField?

akidess: I'm not sure how to use storeOldTime() and oldTime(). I tried something like:

scalar.storeOldTime()

but how do I then revert back to this old value?

I tried this: scalar = scalar.oldTime() but this doesn't seem to do anything.
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Old   June 8, 2010, 04:48
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I'm not too sure about the usage of oldTime either, I just stumbled across it in the code. I would have used it the same way you did (maybe an additional nOldTimes() to see if something was stored).

So if that doesn't work, your own approach seems promising. Can you maybe use

Code:
tmp<scalar> old(IOobject("scalar",runTime.timeName(),mesh,IOobject::MUST_READ,IOobject::AUTO_WRITE),mesh);

//scalar is the variable you want to restore, defined "globally"
scalar == old;
Again, I'm kinda just making guesses using the source guide, but I'm interested in your solution!

- Anton
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Old   June 8, 2010, 10:33
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Thanks for the suggestion. When I try the tmp<scalar> part I get the compiler error:

Code:
error: no matching function for call to Foam::tmp<double>::tmp(Foam::IOobject, Foam::fvMesh&)
note: candidates are: Foam::tmp<T>::tmp(const Foam::tmp<T>&) [with T = double]
note:                 Foam::tmp<T>::tmp(const T&) [with T = double]
note:                 Foam::tmp<T>::tmp(T*) [with T = double]
and when I try the scalar == old part I get:

Code:
error: no match for operator== in scalar == old
note: candidates are: void Foam::GeometricField<Type, PatchField, GeoMesh>::operator==(const Foam::tmp<Foam::GeometricField<Type, PatchField, GeoMesh> >&) [with Type = double, PatchField = Foam::fvPatchField, GeoMesh = Foam::volMesh]
It looks like I'll have to brush up on my C++ although I think this is actually an easy problem to solve.

I'm surprised that this sort of time control isn't more popular amongst foamers since it could dramatically reduce computation time by allowing large/dynamic time steps.
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Old   June 8, 2010, 11:03
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About the first error: We'll have to use a normal scalarField then instead of the tmp<scalar> field. I guess the performance impact won't be noticable anyways.

So did you try

Code:
volScalarField old(IOobject("scalar",runTime.timeName(),mesh,IOobject::MUST_READ,IOobject::AUTO_WRITE),mesh);
restoreScalar == old;
and got an error on "=="? I don't see why that would lead to an error, but you can also see if a regular "=" works. The difference as I understand it is that "=" makes a copy of the field, while "==" will replace the field.

Most Foamers seem happy with the built in time control based on the Courant number. It's good enough for most of my own simulations.
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Old   June 8, 2010, 13:57
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Aha, that seems to have worked! (reading old solution into a new volScalarField and then using scalar == scalar_old). Thanks!

I don't have a Courant number because I don't have a momentum balance in my model (which is why I need to use my own method to control the time step).
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Old   June 9, 2010, 05:14
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Great! I was starting to run out of ideas

I had an unstable case where the time adjustment based on the Courant number would lead to an oscillating time step and bad results, and I think a time step control similar to yours could help there as well. For more stable cases it can be a let-down that this method has no means to increase the timestep.

- Anton
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