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NS eq: 3D unsteady compressible to axisymmetric cylindrical 2D laminar+incompressible |
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November 17, 2015, 04:44 |
NS eq: 3D unsteady compressible to axisymmetric cylindrical 2D laminar+incompressible
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#1 |
New Member
re
Join Date: Nov 2015
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I've been wracking my brain over this question, can anyone shed some light:
Convert 3 dimensional unsteady compressible NS equations to axisymmetric 2 dimensional incompressible laminar form for a cylindrical pipe.ignore gravity I figured I need to use the cylinderical form of NS equations, which is r, theta and z component. But then I'm lost... |
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November 17, 2015, 05:03 |
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#2 |
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Filippo Maria Denaro
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if I am right, a typical set of equations is described in:
J. Fluid Mech., 179, 179-299, 1987 |
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November 17, 2015, 05:15 |
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#3 |
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re
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November 17, 2015, 05:39 |
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#4 |
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Filippo Maria Denaro
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many good textbook illustrate the set of equations you want ...
Maybe, you can find them aslo in the wiki page |
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November 17, 2015, 05:41 |
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#5 |
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Filippo Maria Denaro
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you can start from here http://ingforum.haninge.kth.se/armin..._STOKES_EQ.pdf
and setting the symmetry constraint |
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November 18, 2015, 23:40 |
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#6 | |
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Michael Prinkey
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Quote:
The mass equation will collapse to div U = 0. The energy equation will decouple because there is no density dependence on temperature. The momentum equation will lose the second coefficient of viscosity term because div U = 0. Note that U in the theta direction may be non-zero (swirl velocity), so only d/dtheta terms vanish, not all U_theta terms. |
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November 19, 2015, 08:15 |
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#7 |
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Filippo Maria Denaro
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YEs, I agree ... It is also quite common to start from the set of equations in general vectorial expression, setting all hypotheses (constant density, constant temperature, steady flow, etc.) and derive the vector form of the incompressible equation.
Then the vectors and nabla operators can be expressed in the reference system you want to use |
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November 28, 2015, 05:53 |
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#8 | |
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re
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Quote:
Last edited by rere; November 28, 2015 at 09:10. |
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