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June 12, 2009, 01:04 |
melting process for a pure substance
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#1 |
Senior Member
MASOUD
Join Date: Mar 2009
Posts: 102
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Dear all,
I need to know what are the solidus temperature and liquidus temperature for a pure substance??? Since beta is defined by (T-Ts)/(Tl-Ts), so if I use Ts=Tl=Tm, I will face to dividing bye zero. So what should I do? regards Masoud |
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September 27, 2010, 01:02 |
another equation
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#2 |
New Member
Christiano Santim
Join Date: Sep 2009
Posts: 11
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Dear Masoud
for pure substance, fluent use another equation for liquid fraction
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C Santim Chemical engineer chrisoff22@yahoo.com.br |
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September 27, 2010, 16:53 |
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#3 |
Senior Member
MASOUD
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September 27, 2010, 18:54 |
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#4 | |
New Member
Christiano Santim
Join Date: Sep 2009
Posts: 11
Rep Power: 17 |
Quote:
V. R. Voller and C. Prakash. A Fixed-Grid Numerical Modeling Methodology for Convection-Diffusion Mushy Region Phase-Change Problems. Int. J. Heat Mass Transfer, 30:1709–1720, 1987.
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C Santim Chemical engineer chrisoff22@yahoo.com.br |
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